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3 years ago

HELP PLEASE! write the equation for calculating relative velocity in one dimensional.

Physics

1 answer:

RoseWind [281]3 years ago

6 0

Anwer:

Key Equations

Position Vector: `n r (t) = (t)^j+y

Total acceleration: `n a = `n aC

+ `n aT

Position Vector in frame S is the position Vector in frame S` plus the vector from the origin of S to the origin of S`: `n rPS = `n rPS`

+ `n rS`S

Relative velocity equation connecting two references frame: `n vPS = `n vPS`

+ `n vS`S

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a bike is moving with a velocity of 90km/hr.after applying break it stops in 5 sec. calculate the force applied by brakes .mass

pentagon [3]

Explanation:

initial velocity(u) = 90 km/s = 25 m/s

time (t) = 5 sec

mass (m) = 200 kg

final velocity (v) = 0 m/s

v = u + at

0 = 25 + a * 5

-25 = 5 a

-5 = a

Therefore acceleration = -5m/s²

Force = mass * acceleration

F = 200*-5

F = -1000 N

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3 years ago

A force in the +x-direction with magnitude ????(x) = 18.0 N − (0.530 N/m)x is applied to a 6.00 kg box that is sitting on the ho

fiasKO [112]

Answer:

$v_f=8.17\frac{m}{s}$

Explanation:

First, we calculate the work done by this force after the box traveled 14 m, which is given by:

$W=\int\limits^{x_f}_{x_0} {F(x)} \, dx \\W=\int\limits^{14}_{0} ({18N-0.530\frac{N}{m}x}) \, dx\\W=[(18N)x-(0.530\frac{N}{m})\frac{x^2}{2}]^{14}_{0}\\W=(18N)14m-(0.530\frac{N}{m})\frac{(14m)^2}{2}-(18N)0+(0.530\frac{N}{m})\frac{0^2}{2}\\W=252N\cdot m-52N\cdot m\\W=200N\cdot m$

Since we have a frictionless surface, according to the the work–energy principle, the work done by all forces acting on a particle equals the change in the kinetic energy of the particle, that is:

$W=\Delta K\\W=K_f-K_i\\W=\frac{mv_f^2}{2}-\frac{mv_i^2}{2}$

The box is initially at rest, so $v_i=0$ . Solving for $v_f$ :

$v_f=\sqrt{\frac{2W}{m}}\\v_f=\sqrt{\frac{2(200N\cdot m)}{6kg}}\\v_f=\sqrt{66.67\frac{m^2}{s^2}}\\v_f=8.17\frac{m}{s}$

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3 years ago

After turning off the television, you approach it. As you get close, but not touching it, the hairs on your arm start to stand u

Amanda [17]

The answer is D) induction.

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3 years ago

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A train’s mass is 18181.81 kg. What is its weight?

wel

Answer:

The trains mass in pounds would be 40084.029 if you would round it to the hundreths

Explanation:

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Which formula can be used to solve problems related to the first law of thermodynamics?

docker41 [41]

Answer: The formula used to solve the problems related to first law of thermodynamics is $\Delta U=Q+W$

Explanation:

First law of thermodynamics states that the total energy of the system remains conserved. Energy can neither be destroyed, nor be created but it can only be transformed into one form to another.

Its implication is any change in the internal energy will be either due to heat energy or work energy.

Mathematically,

$\Delta U=Q+W$

where, Q = heat energy

W = work energy

$\Delta U$ = Change in internal energy

Sign convention for these energies:

For Q: Heat absorbed will be positive and heat released will be negative.

For W: Work done by the system is negative and work done on the system is positive.

For $\Delta U$ : When negative, internal energy is decreasing and when positive, internal energy is increasing.

Hence, the formula used to solve the problems related to first law of thermodynamics is $\Delta U=Q+W$

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