No, because we only can land on mar when it's at an appropriate position so that immediately after 516 days, the mar is at the opposite position from the initial position of the earth.
What is the minimum energy?
The minimal kinetic energy required for a pair of moving particles to collide in order for a particle to be produced is known as the threshold energy in particle physics. The threshold energy is always higher than or on par with the desired particle's rest energy.
Answer:
-4.167m/s, 81.2385m
Explanation:
initial velocity=120km/hr = 33.33m/s
final velocity=75km/hr = 20.83 m/s
t=3s
Acceleration=v-u/t
a=(20.83-33.33)/3
a=-12.5/3
a=-4.167
Therefore, the acceleration is -4.167 m/s^2
s=ut+1/2at^2
33.33*3+1/2*-4.167*3^2
81.2385 m
Answer:
v = 1247.92 m/s
Explanation:
The formula for kinetic energy is given as follows:
Another formula that is used for Kinetic Energy is given as:
Comparing both formulae for K.E:
where,
v = rms speed of helium molecule = ?
K = Boltzmann Constant = 1.38 x 10⁻²³ J/k
T = Absolute Temperature = 250 K
m = mass of helium molecule = 6.646 x 10⁻²⁷ kg
Therefore,
<u>v = 1247.92 m/s</u>
Answer:
(a) The velocity of the car before the brakes were applied is 77.46 ft/s
(b) The time required for the car to stop is 7.8 s
Explanation:
Given;
acceleration of the car, a = 10 ft/s²
distance traveled by the car, d = 300 ft
(a) the velocity of the car before the brakes were applied is given;
v² = u² + 2ad
v² = 0 + 2(10 x 300)
v² = 6000
v = √6000
v = 77.46 ft/s
(b) the time required for the car to stop
d = ut + ¹/₂at²
d = 0 + ¹/₂at²
d = ¹/₂at²
t² = 2d / a
t = √ ( 2d / a)
t = √ ( 2 x 300 / 10)
t = 7.8 s
Therefore, the time required for the car to stop is 7.8 s
We have to speed up the watch so we need to decrease time period of pendulum. So we hv to reduce the length.