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Anestetic [448]
3 years ago
15

HELP PLEASE! write the equation for calculating relative velocity in one dimensional.

Physics
1 answer:
RoseWind [281]3 years ago
6 0

Anwer:

Key Equations

Position Vector: `n r (t) = (t)^j+y

Total acceleration: `n a = `n aC

+ `n aT

Position Vector in frame S is the position Vector in frame S` plus the vector from the origin of S to the origin of S`: `n rPS = `n rPS`

+ `n rS`S

Relative velocity equation connecting two references frame: `n vPS = `n vPS`

+ `n vS`S

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Two movers are pushing a large crate with a force of 60.0 n each. one pushes north, the other east. what is the equilibrant forc
romanna [79]
To get the solution you must need to draw a force triangle. Attach the head of the 60N north force arrow with the tail of the 60N east force arrow. The subsequent is the arrow connecting he tail and head of the two arrows. 
You get a right angled triangle, and the resultant is (60^2 + 60^2) ^0.5 = 84.85 N or 85 N northeast.
8 0
3 years ago
explain why radio waves can travel through space,but sound waves cannot.explain the behavior of sound waves and radio waves in s
LUCKY_DIMON [66]
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5 0
3 years ago
An air-track glider undergoes a perfectly inelastic collision with an identical glider that is initially at rest. what fraction
DiKsa [7]
Refer to the diagram shown below.

The initial KE (kinetic energy) of the system is
KE₁ = (1/2)mu²

After an inelastic collision, the two masses stick together.
Conservation of momentum requires that
m*u = 2m*v
Therefore
v = u/2

The final KE is
KE₂ = (1/2)(2m)v²
       = m(u/2)²
       = (1/4)mu²
      = (1/2) KE₁

The loss in KE is
KE₁ - KE₂ = (1/2) KE₁.

Conservation of energy requires that the loss in KE be accounted for as thermal energy.

Answer:  1/2 

5 0
4 years ago
Read 2 more answers
The count rate of a radioactive source decreases from 1600 counts per minute to 400 counts per minute in 12 hours. What is the h
kirill115 [55]

Answer:

t_{1/2}=6 h

Explanation:

Let's use the decay equation.

A=A_{0}e^{-\lambda t}

Where:

  • A is the activity at t time
  • A₀ is the initial activity
  • λ is the decay constant

We know that \lambda=\frac{ln(2)}{t_{1/2}}

So we have:

\lambda=\frac{ln(A/A_{0})}{t}

\frac{ln(2)}{t_{1/2}}=\frac{ln(A/A_{0})}{t}

t_{1/2}=\frac{t*ln(2)}{ln(A/A_{0})}

t_{1/2}=6 h

Therefore, the half-life of the source is 6 hours.

I hope it helps you!

4 0
3 years ago
Provide an example of a material that transmits, reflects, and absorbs light simultaneously?
den301095 [7]
A Mirror



Space for 20 letters
5 0
3 years ago
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