Answer:
Explanation:
Because the spaceships are traveling in the same direction, you should subtract the speed of spaceship A from the speed of spaceship B in order to calculate 
.
I haven't worked on Part-A, and I don't happen to know the magnitude of the gravitational force that the Sun exerts on the Earth.
But whatever it is, it's exactly, precisely, identical, the same, and equal to the magnitude of the gravitational force that the Earth exerts on the Sun.
I think that's the THIRD choice here, but I'm not sure of that either.
Answer:
Explanation:
Using Kepler's third law, we can relate the orbital periods of the planets and their average distances from the Sun, as follows:
Where 
and 
are the orbital periods of Mercury and Earth respectively. We have 
and 
. Replacing this and solving for
Answer:
The answer will be the first one.
Explanation:
Divide
Answer:
1. 230 kg...
W = m * g
W= 230 kg * 9.81 m/s^2
<u>W= 2256,3 N</u>
m= 230kg , W = 2256,3 N , g= 9.81 m/s^2
2. 887 N
W= m * g
887 N = m * 9.81 m/s^2
<u>m= 90,42 kg</u>
m= 90,42 kg, W = 887 N , g= 9.81 m/s^2
3. 420 kg
W= m * a
w= 420 kg * 9.81 m/s^2
<u>w=</u><u> </u><u>4120,2 N</u>
m= 420 kg , W = 4120,2 N , g= 9.81 m/s^2
4. Determine the gravity on Pluto where a 15 kg object weighs 55.5N.
w = m * g
55.5 N = 15 kg * g
<u>a= 3,7 m/s^2</u>
m = 15 kg , W= 55.5 N , g= 3,7 m/s^2
