Answer:
-1
Step-by-step explanation:
m = y2 - y1 / x2 - x1
= 1 - 4 / 8 - 5
= -3 / 3
= -1
Answer: 0.8413
Step-by-step explanation:
Given : Henry has collected data to find that the typing speeds for the students in a typing class has a normal distribution.
Mean :
Standard deviation : 
Let x be the random variable that represents the typing speeds for the students.
The z-score :-

For x= 51

Using the standard normal distribution table ,the probability that a randomly selected student has a typing speed of less than 51 words per minute :-

Hence, the probability that a randomly selected student has a typing speed of less than 51 words per minute = 0.8413
Answer:
31 emails, but I can't do a # number line.
Step-by-step explanation:
X: liters of 15% orange juice
y: liters of 10% orange juice
x+y=5L
y=5L - x
x liters of 15% orange juice plus y liters of 10% orange juice makes 5 liters of 12% orange juice in equation form:
0.15x+0.10y = 0.12(5L)
0.15x+0.10(5L-x)=0.12(5L)
0.15x+0.5-0.10x=0.6
0.05x=0.1L
x=2L
so y = 3L
so you need 2 liters of 15% orange juice and 3 liters of 10% orange juice