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Kobotan [32]
3 years ago
13

In a double-slit experiment, two beams of coherent light traveling different paths arrive on a screen some distance away. What i

s the path difference between the two waves corresponding to the third bright band out from the central bright band?
Physics
1 answer:
andrew11 [14]3 years ago
3 0
Destructive interference occurs when path difference = ½-integer multiple of the wavelength i.e. Minima in diffraction pattern given by, = ! + # λ = !1 + # λ = 3λ/2 m
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A roller coaster car is elevated to a height of 30 m and released from rest to roll along a track. At a certain time T it is at
Naddika [18.5K]

Explanation:

Initial energy = final energy + work done by friction

PE = PE + KE + W

mgH = mgh + 1/2 mv² + W

(800)(9.8)(30) = (800)(9.8)(2) + 1/2 (800) v² + 25000

v = 22.1 m/s

Without friction:

PE = PE + KE

mgH = mgh + 1/2 mv²

(800)(9.8)(30) = (800)(9.8)(2) + 1/2 (800) v²

v = 23.4 m/s

4 0
3 years ago
Which of the following is not an element of installment credit?
Alex787 [66]

Answer:

c line of credit I believe

5 0
3 years ago
If an astronaut throws an object in space, the object's speed will _____________. A) decrease. B) increase. C) remain constant.
GenaCL600 [577]

The object's speed will remain constant after the it leaves his hand.

So will HIS speed in the opposite direction.

7 0
3 years ago
Read 2 more answers
A sports car is advertised to be able to stop in a distance of 50.0 m from a speed of 80 km. What is its acceleration and how ma
Flauer [41]

Explanation:

Given that,

Initial speed of the sports car, u = 80 km/h = 22.22 m/s

Final speed of the runner, v = 0

Distance covered by the sports car, d = 80 km = 80000 m

Let a is the acceleration of the sports car.  It can be calculated using third equation of motion as :

v^2-u^2=2ad

a=\dfrac{v^2-u^2}{2d}

a=\dfrac{0-(22.22)^2}{2\times 80000}

a=-0.00308\ m/s^2

Value of g, g=9.8\ m/s^2

a=\dfrac{-0.00308}{9.8}\ m/s^2

a=(-0.000314)\ g\ m/s^2

Hence, this is required solution.

8 0
3 years ago
Scientists measure the time between the arrival of an earthquake's _______ and _______ waves to help determine the distance betw
soldier1979 [14.2K]

Scientists measure the time between the arrival of an earthquake's __P____ and ___S____ waves to help determine the distance between the recording seismograph and the earthquake epicenter.

Explanation:

P- (compressional) and S- (shear) waves produced in earthquakes travel at different speeds. P waves are faster than S waves and hence will be detected first by a seismograph after an earthquake. The further away a seismograph is from the epicenter of an earthquake,  the longer the time difference between the two (2) waves will be.

Using several, at least 3, seismographs located at different geoghraphical locations and detecting earthquakes, geologists can extrapolate the epicenter of an earthquake using the time differences in arrivals of the two waves in each of the seismographs, using the mathematics of triangulation.

Learn More:

For more on P- and S-- waves check out;

brainly.com/question/11915788

brainly.com/question/11334414

brainly.com/question/2530620

#LearnWithBrainly

7 0
3 years ago
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