Answer:
The acceleration is 2.2 m/s^2
Explanation:
In the attached image, we can see the free body diagram. And using the second law of Newton it will be possible to find the acceleration of the box.
Answer:
The energy becomes 4 times greater.
Explanation:
We know that the energy of a wave is proportional to the square of its amplitude
E ∝ Amplitude^2
Since the original amplitude = 0.5 m
and the new amplitude becomes = 1 m
We are doubling the amplitude. This means that the new energy will be affected by a factor of 4
E_new ∝ (2*Amplitude)^2 =
E_new ∝ 4*(Amplitude)^2
E_new = 4*E
Answer:
mb = 3.75 kg
Explanation:
System of forces in balance
ΣFx =0
ΣFy = 0
Forces acting on the box
T₁ : Tension in string 1 ,at angle of 50° with the horizontal on the left
T₂ = 40 N : Tension in string 2, at angle of 75° with the horizontal on the right.
Wb :Weightt of the box (vertical downward)
x-y T₁ and T₂ components
T₁x= T₁cos50°
T₁y= T₁sin50°
T₂x= 30*cos75° = 7.76 N
T₂y= 30*sin75° = 28.98 N
Calculation of the Wb
ΣFx = 0
T₂x-T₁x = 0
T₂x=T₁x
7.76 = T₁cos50°
T₁ = 7.76 /cos50° = 12.07 N
ΣFy = 0
T₂y+T₁y-Wb = 0
28.98 + 12.07(cos50°) = Wb
Wb = 36.74 N
Calculation of the mb ( mass of the box)
Wb = mb* g
g: acceleration due to gravity = 9.8 m/s²
mb = Wb/g
mb = 36.74 /9.8
mb = 3.75 kg
Answer:
6 second
Explanation:
initial velocity of ball, u = 60 m/s
g = 10 m/s^2
Let the ball takes time t to reach at the maximum height
We know that at maximum height, the velocity of ball is zero.
v = 0 m/s
Use first equation of motion
v = u + gt
0 = 60 - 10 x t
t = 6 second
Thus, the ball takes 6 second to reach to maximum height.
