r₁ = distance of point A from charge q₁ = 0.13 m
r₂ = distance of point A from charge q₂ = 0.24 m
r₃ = distance of point A from charge q₃ = 0.13 m
Electric field by charge q₁ at A is given as
E₁ = k q₁ /r₁² = (9 x 10⁹) (2.30 x 10⁻¹²)/(0.13)² = 1.225 N/C towards right
Electric field by charge q₂ at A is given as
E₂ = k q₂ /r₂² = (9 x 10⁹) (4.50 x 10⁻¹²)/(0.24)² = 0.703 N/C towards left
Since the electric field in left direction is smaller, hence the electric field by the third charge must be in left direction
Electric field at A will be zero when
E₁ = E₂ + E₃
1.225 = 0.703 + E₃
E₃ = 0.522 N/C
Electric field by charge "q₃" is given as
E₃ = k q₃ /r₃²
0.522 = (9 x 10⁹) q₃/(0.13)²
q₃ = 0.980 x 10⁻¹² C = 0.980 pC
Answer:
180m
Explanation:
We can use the formula [ d = st ].
12 * 15 = 180m
Best of Luck!
Answer:
![\phi_i = BA](https://tex.z-dn.net/?f=%5Cphi_i%20%3D%20BA)
Explanation:
magnetic flux is the count of magnetic field lines passing through a given loop or area
As we know that magnetic flux is given by the formula
![\phi = \vec B. \vec A](https://tex.z-dn.net/?f=%5Cphi%20%3D%20%5Cvec%20B.%20%5Cvec%20A)
here we also know that magnetic field B and plane of the coil is perpendicular in initial position
So the area vector is always perpendicular to the plane of the coil
so the angle between magnetic field and area vector is parallel to each other and this angle would be zero
so magnetic flux of the coil initially we have
![\phi = BAcos0 = BA](https://tex.z-dn.net/?f=%5Cphi%20%3D%20BAcos0%20%3D%20BA)
THE MINI
Alec Issigonis, 1959
The Telephone
Alexander Graham Bell, 1876
http://www.radiotimes.com/news/2013-01-08/the-50-greatest-british-inventions