All categories

3 years ago

A mass of the crucible (g) 88.000g

1 answer:

4 0

A)5.000g
b)mole=mass/molarmass
   molar mass of H2O=18g
   mass of water=5g
b)mole of water=5.000/18.000=0.2778g
c)mass of salt=2.342g
d)mole of salt=mass/molar mass
   pure salt is NaCl
   molar mass of NaCl=58.50g
d)mole of salt=2.342/58.5=0.040mol
e)mole ratio=0.27:0.04

You might be interested in

An atom requires 6.24 × 10−19J to remove its furthest electron in the gas phase. What is the maximum wavelength of electromagnet

daser333 [38]

Report your numerical answer in units of nm. Use significant figur

3 0

2 years ago

Read 2 more answers

Given the following information, what is the concentration of H2O(g) at equilibrium? [H2S](eq) = 0.671 M [O2](eq) = 0.587 M Kc =

MAVERICK [17]

Answer: The equilibrium concentration of water is 0.597 M

Explanation:

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_{c}$

For a general chemical reaction:

$aA+bB\rightleftharpoons cC+dD$

The expression for $K_{eq}$ is written as:

$K_{c}=\frac{[C]^c[D]^d}{[A]^a[B]^b}$

The concentration of pure solids and pure liquids are taken as 1 in the expression.

For the given chemical reaction:

$2H_2S(g)+O_2(g)\rightleftharpoons 2S(s)+2H_2O(g)$

The expression of $K_c$ for above equation is:

$K_c=\frac{[H_2O]^2}{[H_2S]^2\times [O_2]}$

We are given:

$[H_2S]_{eq}=0.671M$

$[O_2]_{eq}=0.587M$

$K_c=1.35$

Putting values in above expression, we get:

$1.35=\frac{[H_2O]^2}{(0.671)^2\times 0.587}$

$[H_2O]=\sqrt{(1.35\times 0.671\times 0.671\times 0.587)}=0.597M$

Hence, the equilibrium concentration of water is 0.597 M

8 0

3 years ago

Is h3co3 a strong base

tamaranim1 [39]

I read and said it's a weak base

3 0

2 years ago

Ametal used in hot water system?

svet-max [94.6K]

Answer:

Nichrome

Answer: Hot water system coils are commonly made up of metal alloys which are a combination of two or more elements. The most commonly used metal alloy is “Nichrome”. Nichrome is an alloy of nickel (80%) and chromium (20%).

5 0

2 years ago

A block of aluminum with a mass of 140 g is cooled from 98.4°C to 62.2°C with a release of 4817 J of heat. From these data, calc

disa [49]

Answer:

specific heat = 0.951 j/g·°C

Explanation:

Heat flow equation => q = m·c·ΔT

q = heat flow = 4817 joules

m = mass in grams = 140 grams Aluminum

c = specific heat = ?

ΔT = Temperature Change in °C = 98.4°C - 62.2°C = 36.2°C

q = m·c·ΔT => c = q/m·ΔT = 4817j/(140g)(36.2°C) = 0.951 j/g·°C

6 0

2 years ago