Answer:
0.295 g Co
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Explanation:
<u>Step 1: Define</u>
3.01 × 10²¹ atoms Co
<u>Step 2: Identify Conversions</u>
Avogadro's Number
Molar Mass of Co - 58.93 g/mol
<u>Step 3: Convert</u>
<u /> = 0.294552 g Co
<u>Step 4: Check</u>
<em>We are given 3 sig figs. Follow sig fig rules and round.</em>
0.294552 g Co ≈ 0.295 g Co
The molar Concentration of KMnO₄ is 0.000219 M
Concentration is the abundance of a constituent divided by means of the overall extent of an aggregate. numerous styles of mathematical description may be outstanding: mass awareness, molar awareness, variety concentration, and quantity awareness.
y is absorbance
x is the molar concentration of KMnO_4
y = 4.84E + 03x - 2.26E - 01
0.833 = 4.84 * 10⁺⁰³ x - 2.26 * 10⁻¹
1.059 = 4.84 * 10⁺⁰³ x
X = 0.000219 M
Hence, The molar Concentration of KMnO₄ is 0.000219 M
Learn more about concentration here:-brainly.com/question/14469428
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Answer:
In the valence shell, it should have 8 valence electrons.
Explanation: