9.8m per seccond is the speed of gravity if you drop something like a ball from a tower
Answer:
At an angle of ![30^{\circ}](https://tex.z-dn.net/?f=30%5E%7B%5Ccirc%7D)
Explanation:
Assume the river flows from East to West so for the swimmer to cross across it, assume he crosses it from West to East.
The resultant speed will be given by
![R= \sqrt {10^{2}-5^{2}=\sqrt {75}\approx 8.66 km/h\\Direction=sin^{-1}\frac {5}{10}\approx 30^{\circ}](https://tex.z-dn.net/?f=R%3D%20%5Csqrt%20%7B10%5E%7B2%7D-5%5E%7B2%7D%3D%5Csqrt%20%7B75%7D%5Capprox%208.66%20km%2Fh%5C%5CDirection%3Dsin%5E%7B-1%7D%5Cfrac%20%7B5%7D%7B10%7D%5Capprox%2030%5E%7B%5Ccirc%7D)
Newtons first law of motion is also known as the law of inertia
Answer:
The answer to your question is
Explanation:
Data
mass = 0.5kg
T1 = 35
T2 = ?
Q = - 6.3 x 10⁴ J = - 63000 J
Cp = 4184 J / kg°C
Formula
Q = mCp(T2 - T1)
T2 = T1 + Q/mCp
Substitution
T2 = 35 - 63000/(0.5 x 4184)
T2 = 35 - 63000/2092
T2 = 35 - 30.1
T2 = 4.9 °C