What will a spring scale read for the weight of a 57.0-kg woman in an elevator that moves upward with constant speed of 5.0 m/s
1 answer:
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Answer:
-24 m/s
Explanation:
mass of the bowling ball = 3 kg
time (t) = 0.3 seconds
Force = 24 N
initial velocity u = ???
We know that;
Force = mass × acceleration (a)
So;
24 = 3 × a
a = 24/3
a = 8 m/s²
Also;
From equation of motion; acceleration is given by the relation;
if v = 0
then ;
24 = 0- u
u = -24 m/s
Thus; the initial velocity of the bowling ball when it first touched the mattress = -24 m/s
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