Answer:
F(friction) = μ M g definition of frictional force
μ = F / (M g) = 11 N / 50 N = .22
0.2 is the value of coefficient of friction (k)
F=kN
F=horizontal force
n=Normal Force
k=coefficient of friction
k=F/N
k=200/1000
k=0.2
The ratio of the normal force pushing two surfaces together to the frictional force preventing motion between them is known as the friction coefficient. Usually, the Greek letter mu is used to indicate it .N is the normal force, and F is the frictional force, hence F = N/N.
Due to the fact that both F and N are measured in units of force, the coefficient of friction has no dimensions (such as newtons or pounds). The coefficient of friction can have a variety of values for both static and dynamic friction. Static friction occurs when an object encounters friction that resists any applied force, keeping the object at rest until the static frictional force is released. In kinetic friction, the frictional force resists the motion of the object.
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Answer:
The size of the image is 1.04 m.
Explanation:
Given that,
Height of object = 2.40 m
Distance of object = 2.60 m
Radius of curvature =4.00 m
Focal length 
We need to calculate the image distance
Using mirror formula
We need to calculate the height of the image
Using formula of magnification
Put the value into the formula
Hence, The size of the image is 1.04 m
Answer:
part A ⇒ u = 1.28 m
part B ⇒v = 0.43 m
Explanation:
for u is the distance to the object from the mirror and v is the distance from the mirror to the image.
Part A:
the mirror equation is given by:
1/f = 1/v + 1/u
but we told that, v = 1/3u:
1/f = 3/v + 1/u = 4/u
1/f = 4/u
f = u/4
u = 4f
= 4×(32×10^-2)
= 1.28 m
Therefore the distance from the mirror to the object is 1.28 m.
part B:
v = 1/3×u = 1/3×(1.28) = 0.43 m
Answer:
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