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3 years ago

I NEED YOUR HELP! Use the net to find the lateral area of the prism. Answer: m^2

Mathematics

2 answers:

egoroff_w [7]3 years ago

6 0

Ok, to solve this, once again you need to fold this map back up into a 3d shape ( in your head).
What you should see is that the little overhanging sides that had no measurement, now have a measurement. They measure up to be the same as the 3m. sides.
so to find the area of all the rectangles, you need to multiply the base times height. (b)h
I will start from the left of your pic. and work my way to the right...not including the little overhanging ones.
The first one should measure out to be 3(15) =45
The second to be 6(15) =90
The third to be 3(15) =45
The fourth to be 6(15) =90 :)
So you have these, but now you need to get the little over hangers I call them...lol.
The width is 6, same as the rectangle they are attached to. And the picture in your mind should tell you that the height is 3, the same as the width of the skinny rectangles that they attach to in your mind.
Soooo now they measure out to be 3(6) =18. and you just multiply this by two because they are the same area, right? So that would be 36.
ok. Now add all of the areas of the surfaces 45+90+45+90+36 to get a total surface area of.... *drummel please* 306m^2
this means 306m. to the power of 2 if you didn't know.
well, I hope you understand better and I hope I helped! ;)

Elodia [21]3 years ago

6 0

Lat
no top or bottom

top is 15 by 6

sides are
3 by 15+6 by 3+6 by 3+3 by 15
45+18+18+45=126 m^2

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Step-by-step explanation:

An explanatory variable is a type of independent variable. An explanatory variable is that variable that explains changes in another variable. It can be anything that might affect the response variable. The explanatory variable is used to predict or explain differences in the response variable. In an experimental or research study, the explanatory variable is the variable that is manipulated by the researcher.

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Explanatory variable: Extra support by faculties.

The response variable is also known as the dependent/outcome variable. Here, its value can be predicted or its variation can be explained by the explanatory variable. In an experimental study, this is the outcome that is measured after manipulation of the explanatory variable

From the question above,

Response variable: whether community college students who have assess into elementary algebra could be successful if they were placed directly into college-level statistics.

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3 years ago

Calculate the gradient of the straight line which joins A(2,-3) and B(6,9)

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Answer:

Gradient: m = 3

Step-by-step explanation:

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3 years ago

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Given:

One linear function represented by the table.

Another linear function represented by the graph.

To find:

The greater unit rate and greater y-intercept.

Solution:

Formula for slope (unit rate):

$m=\dfrac{y_2-y_1}{x_2-x_1}$

From the given table it is clear that the linear function passes through (0,5) and (5,15). The function intersect the y-axis at (0,15), so the y-intercept is 15.

$m_1=\dfrac{15-5}{5-0}$

$m_1=\dfrac{10}{5}$

$m_1=2$

So, the unit rate of first function is 2.

From the given graph it is clear that the linear function passes through (0,6) and (-4,0). The function intersect the y-axis at (0,6), so the y-intercept is 6.

$m_2=\dfrac{0-6}{-4-0}$

$m_2=\dfrac{-6}{-4}$

$m_2=\dfrac{3}{2}$

So, the unit rate of first function is $\dfrac{3}{2}$ .

Now,

$2>\dfrac{3}{2}$

$m_1>m_2$

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$15>6$

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fiasKO [112]

I believe you need to solve this using the quadratic formula!
To begin, this is what it is:
x= -b ± √ b^2 - 4ac / 2a
Just plug in what you have in your problem...
2 being a, 13 being b, and -24 being c.
So we get:
x= -13 ± √13^2 - 4(2)(-24) / 2(2)
x= -13 ± √169 - 8 (-24) / 4
x= -13 ± √169 + 192 / 4
x= -13 ± √361 / 4
The square root of 361 is 19.
So you have: -13 ± 19 / 4.
Here's where you take the equation -13 ± 19 and put the addition and subtraction sign to use.
-13 - 19 = -32
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-13 + 19 = 6
Now all is left to do is divide the two numbers by 4.
-32/4 = -8
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6/4 = 3/2

x = -8, 3/2

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3 years ago