Answer:
a)Counterclockwise
b)ω=2 rad/s
Explanation:
Given that
Object at = --2 m
r= - 2 m
Velocity pf object V = - 4 m/s
We know that
r= - 2 i m
V= - 4 j m/s
- 4 j= ω x (- 2 i)
ω should be in counter clockwise (k) to satisfy the above equation.
It means that the direction of object will in counter clockwise.
4 = ω x 2
ω=2 rad/s
So object velocity at 2 m will be 2 rad/s.
Answer:
a)
b)
Explanation:
Given:
The mass of the stone:
Now the acceleration of the stone opposite of the motion:
where:
d = deceleration
<u>In course of going up the net acceleration on the stone will be:</u>
a)
Now using the equation of motion:
where:
final velocity when the stone reaches at the top of the projectile = 0
h = height attained by the stone before starting to fall down
b)
during the course of descend from the top height of the projectile:
initial velocity,
The acceleration will be:
here the gravity still acts downwards but the drag acceleration acts in the direction opposite to the motion of the stone, now the stone is falling down hence the drag acts upwards.
Using equation of motion:
(+ve acceleration because it acts in the direction of motion)