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topjm [15]
3 years ago
6

An object moves at constant speed along a circular path in a horizontal plane, with the center at the origin. When the object is

at –2.0 m, its velocity is –(4.0 m/s). In which direction is the object traveling? Clockwise Counterclockwise (b) What is the object’s velocity at 2.0 m?
Physics
1 answer:
guapka [62]3 years ago
6 0

Answer:

a)Counterclockwise

b)ω=2 rad/s

Explanation:

Given that

Object at = --2 m

r= - 2 m

Velocity pf object V = - 4 m/s

We know that

\vec{V}=\vec{\omega }\times \vec{r}

r= - 2 i m

V= - 4 j m/s

- 4 j= ω x (- 2 i)

ω  should be in counter clockwise (k) to satisfy the above equation.

It means that the direction of object will in counter clockwise.

4 = ω x 2

ω=2 rad/s

So object velocity at 2 m will be 2 rad/s.

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Answer:

The average acceleration is 8\ m/s^2

Explanation:

<u>Uniform Acceleration </u>

When an object varies its velocity at the same rate, the acceleration is constant.

The relation between the initial and final speeds is:

v_f=v_o+a.t

Where:

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The acceleration can be calculated by solving for a:

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The Indy 500 race car increases its speed from vo=4 m/s to vf=36 m/s in t=4 s. Thus, the average acceleration is:

\displaystyle a=\frac{36-4}{4}=8\ m/s^2

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