An important difference between a universal and a split-phase motor is that the split-phase motor has
A. two brushes attached to the stator.
B. a single coil formed on the rotor.
<u>C. two windings on the stator. </u>
D. an armature with a commutator.
Answer:
Average speed = 5 m/s
Explanation:
Given the following data;
Distance = 100m
Time = 20 secs
To find the average speed;
Speed = distance/time
Substituting into the formula, we have;
Speed = 100/20
Speed = 5m/s
Therefore, Elsa's average speed is 5 meters per seconds.
Answer:
(A) 2.4 N-m
(B) 
(C) 315.426 rad/sec
(D) 1741.13 J
(E) 725.481 rad
Explanation:
We have given mass of the disk m = 4.9 kg
Radius r = 0.12 m, that is distance = 0.12 m
Force F = 20 N
(a) Torque is equal to product of force and distance
So torque
, here F is force and r is distance
So 
(B) Moment of inertia is equal to 
So 
Torque is equal to 
So angular acceleration 
(C) As the disk starts from rest
So initial angular speed 
Time t = 4.6 sec
From first equation of motion we know that 
So 
(D) Kinetic energy is equal to 
(E) From second equation of motion

Technically, we don't have the information needed to calculate the current,
because you haven't mentioned the units of the 3.5 .
Since the 3.5 is a resistance, we strongly suspect ... and we'll therefore
assume ... that the 3.5 has the units of ohms. Then . . .
Current = (voltage) / (resistance) = (1.5/3.5) = <em>3/7 of an Ampere</em>.
(429 mA, rounded)
The time for the police car to catch up with the speeding motorist is 7.6 seconds.
<h3>What time will the police car catch up with the speeding motorist?</h3>
The police car and the motorist will cover equal distances.
Let the distance covered be d.
Distance covered by the motorist = speed * time
time = t, speed = 30 m/s
d = 30t
Distance covered by the police car = acceleration * (time)
time = t - 2, acceleration = 5.0 m/s²
d = 5(t-2)²
d = 5(t² - 4t + 4)
d = 5t² - 20t + 20
Equating the two equations for distance
5t² - 20t + 20 = 30t
5t² - 50t + 20 = 0
Solving for t using the quadratic formula:
t = 9.6 second or 0.4 seconds
Since t > 2, t = 9.6 seconds
t - 2 = 9.6 - 2
t - 2 = 7.6 seconds
Therefore, the time for the police car to catch up with the speeding motorist is 7.6 seconds.
Learn more about distance and acceleration at: brainly.com/question/14344386
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