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Vlad [161]
3 years ago
10

If a compound containing only magnesium and oxygen consists of 0.564 g mg and 0.376 g o, what is the compound's empirical formul

a..
Chemistry
1 answer:
jasenka [17]3 years ago
3 0
    the   Empirical  formula    of  the  compound  is  calculated    as  follows

find  the  moles  of  each  element
moles =  mass/molar  mass

that  is Magnesium= 0.564 g /24 g/mol  = 0.0235  moles

For  oxygen    =  0.376 g /16 g/mol=  0.0235  moles
find  the   mole  ratio  by  dividing   both     moles  of  by  0.0235 moles

magnesium =  0.0235/0.0235= 1mole
oxygen=  0.0235 /0.0235= 1mole

therefore  the  empirical    formula  =  MgO
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Answer:

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Explanation:

1.3 x 10^12

We want to convert this from scientific notation.

Tip: in scientific notation the exponent tells you how many place you move the decimal point over. If the exponent is negative you move the decimal point to the left. Ex. For, 4.1 x 10^-8, we would move the decimal point over 8 times to the left to get .00000041. When the exponent is positive we move over to the right. Ex. For, 7.6 x 10^7 we would move the decimal point over 7 times to the right to get 76,000,000

So to convert 1.3 x 10^12 we simply move over the decimal point over 12 times to the right.

1.3 x 10^12 ------> 1,300,000,000,000

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