Lilium lancifolium is an autotroph since it is a plant and makes its own food through photosynthesis.
Explanation:
An object can possess energy in tow ways by it's motion or position
Answer:
[HI] = 0.7126 M
Explanation:
Step 1: Data given
Kc = 54.3
Temperature = 703 K
Initial concentration of H2 and I2 = 0.453 M
Step 2: the balanced equation
H2 + I2 ⇆ 2HI
Step 3: The initial concentration
[H2] = 0.453 M
[I2] = 0.453 M
[HI] = 0 M
Step 4: The concentration at equilibrium
[H2] = 0.453 - X
[I2] = 0.453 - X
[HI] = 2X
Step 5: Calculate Kc
Kc = [Hi]² / [H2][I2]
54.3 = 4x² / (0.453 - X(0.453-X)
X = 0.3563
[H2] = 0.453 - 0.3563 = 0.0967 M
[I2] = 0.453 - 0.3563 = 0.0967 M
[HI] = 2X = 2*0.3563 = 0.7126 M
212 ml of lead nitrate is required to prepare a dilute solution of 820.7 ml of lead nitrate.
Answer:
Option A.
Explanation:
Similar to Avagadro's law, there is another law termed as dilution law. As the product of volume and normality of the reactant is equal to the product of volume and normality of the product from the Avagadro's law. In dilution law, it will be as product of volume and concentration of the solute of the reactant is equal to the product of volume and concentration of solution.
![C_{1} V_{1} =C_{2} V_{2}](https://tex.z-dn.net/?f=C_%7B1%7D%20V_%7B1%7D%20%3DC_%7B2%7D%20V_%7B2%7D)
So, as per the given question C1 = 5.45 M of lead nitrate and V1 has to be found. While C2 is 1.41 M of lead nitrate and V2 is 820.7 ml.
Then, ![(5.45*V_{1} ) = (820.7*1.41)](https://tex.z-dn.net/?f=%285.45%2AV_%7B1%7D%20%29%20%3D%20%28820.7%2A1.41%29)
![V_{1}=\frac{820.7*1.41}{5.45}= 212.33 ml](https://tex.z-dn.net/?f=V_%7B1%7D%3D%5Cfrac%7B820.7%2A1.41%7D%7B5.45%7D%3D%20%20212.33%20ml)
So nearly 212 ml of lead nitrate is required to prepare a dilute solution of 820.7 ml of lead nitrate.
Answer: 1. A, 2.B, 3. D, 4. B, 5. C
Explanation:
i have P.E. too lol have a great day!