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Vika [28.1K]
4 years ago
15

An ionic bond will form between ?​

Chemistry
2 answers:
pickupchik [31]4 years ago
5 0

An ionic bond is a type of chemical bond formed through an electrostatic attraction between two oppositely charged ions. Ionic bonds are formed between a cation, which is usually a metal, and an anion, which is usually a nonmetal. A covalent bond involves a pair of electrons being shared between atoms.

plz mark me as brainliest if this helped :)

balu736 [363]4 years ago
3 0
Ionic bond is when a positively charged ion forms a bond with a negatively charged ions and one atom transfers electrons to another
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What are the errors in the table? Check all that apply.
Zanzabum

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Explanation:

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3 years ago
How does granite differ from gabbro in coloring and
svetoff [14.1K]

Explanation:

Igneous rocks are formed by the crystallisation of a magma. The difference between granites and basalts is in silica content and their rates of cooling. A basalt is about 53% SiO2, whereas granite is 73%. Intrusive, slowly cooled inside the crust.

8 0
4 years ago
The Goodyear blimp we usually see hovering above our heads at a football game contains 5600 m3 of helium gas. If there are 1070
Alina [70]

Answer:

277.16 K is the temperature of the gas.

Explanation:

Using ideal gas equation:

PV = nRT

where,

P = Pressure of gas = 1.10\times 10^5 Pa

V = Volume of gas = 5600 m^3

n = number of moles of gas = \frac{1,070 kg}{4.00260 g/mol}=\frac{1,070,000 g}{4.00260 g/mol}=267,326.24 mol

R = Gas constant = 8.314 J/mol.K

T = Temperature of gas = ?

Putting values in above equation, we get:

T=\frac{PV}{RT}

T=\frac{1.10\times 10^5 Pa\times 5,600 m^3}{267,326.24 mol\times 8.314 J/mol K}

T = 277.16 K

277.16 K is the temperature of the gas.

8 0
3 years ago
The overall reaction 2Co3+(aq) + 2Cl–(aq) → 2Co2+(aq) + Cl2(g) has the standard cell voltage E°cell = 0.46 V. Given E° = 1.36 V
Ede4ka [16]

<u>Answer:</u> The standard reduction potential for reduction half reaction is 1.82 V

<u>Explanation:</u>

The given chemical reaction follows:

2Co^{3+}(aq.)+2Cl^(aq.)\rightarrow 2Co^{2+}(aq.)+Cl_2(g)

<u>Oxidation half reaction:</u>  2Cl^-\rightarrow Cl_2+2e^-

<u>Reduction half reaction:</u>  Co^{3+}+e^-\rightarrow Co^{2+}

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

We are given:

E^o_{Cl_2/2Cl^-}=1.36V\\\\E^o_{cell}=0.46V

Putting values in above equation, we get:

0.46=E^o_{Co^{3+}/Co^{2+}}-1.36\\\\E^o_{Co^{3+}/Co^{2+}}=(0.46+1.36)V=1.82V

Hence, the standard reduction potential for reduction half reaction is 1.82 V

6 0
3 years ago
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