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Kryger [21]
3 years ago
7

During an experiment, it is observed that iron powder sinks in water and sulfur powder floats in water. What will most likely be

observed when sulfur powder and iron powder are mixed together and then added to water?
Sulfur will float and iron will sink because each will retain its properties.
Iron will float and sulfur will sink because each will lose its properties.
Both will float because they are physically mixed.
Both will float because they react chemically.

someone pls help me, i literally don't understand chem
Ill give 50 points
Chemistry
2 answers:
lutik1710 [3]3 years ago
7 0

Sulfur will float, and iron will sink because each will retain its properties.

“Iron will float, and sulfur will sink because each will lose its properties” is <em>incorrect</em>. A substance will lose its properties only if it reacts to form a new substance.

“Both will float because they are physically mixed” is <em>incorrect</em>. The substances in a mixture retain their properties.

“Both will float because they react chemically” is <em>incorrect</em>. Iron and sulfur do not react at room temperature. Even if they did, the iron sulfide would sink.

irga5000 [103]3 years ago
6 0

Answer:

Sulfur will float and iron will sink because each will retain its properties.

Explanation:

This is the correct answer because sulfur powder and iron powder are two different things, with different properties. Even if they are added to water and mixed around, they still retain their properties since no actual chemical activity was performed on them (they were just mixed by physical means). Hence, the sulfur will float back up, as it does initially, and the iron will sink, as it had initially.

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Calculate the molecular weight of a substance. In which the solution of this substance in the water has a concentration of 7 per
Eduardwww [97]

Answer : The molecular weight of a substance is 157.3 g/mol

Explanation :

As we are given that 7 % by weight that means 7 grams of solute present in 100 grams of solution.

Mass of solute = 7 g

Mass of solution = 100 g

Mass of solvent = 100 - 7 = 93 g

Formula used :  

\Delta T_f=i\times K_f\times m\\\\T_f^o-T_f=k_f\times\frac{\text{Mass of substance(solute)}\times 1000}{\text{Molar mass of substance(solute)}\times \text{Mass of water(solvent)}}

where,

\Delta T_f = change in freezing point

T_f^o = temperature of pure water = 0^oC

T_f = temperature of solution = -0.89^oC

K_f = freezing point constant of water = 1.86^oC/m

m = molality

Now put all the given values in this formula, we get

(0-(-0.89))^oC=1.86^oC/m\times \frac{7g\times 1000}{\text{Molar mass of substance(solute)}\times 93g}

\text{Molar mass of substance(solute)}=157.3g/mol

Therefore, the molecular weight of a substance is 157.3 g/mol

7 0
3 years ago
Example of false solutions and true solutions <br>​
Kamila [148]

Answer:

answer in expl.

Explanation:

example of false solution.- Earth is not square

true eg. - we live in earth

3 0
3 years ago
How many grams of F− must be added to a cylindrical water reservoir having a diameter of 2.02 × 102 m and a depth of 87.32 m?
aksik [14]

Complete Question:

To aid in the prevention of tooth decay, it is recommended that drinking water contain 0.800 ppm fluoride. How many grams of F− must be added to a cylindrical water reservoir having a diameter of 2.02 × 102 m and a depth of 87.32 m?

Answer:

2.23x10⁶ g

Explanation:

The concentration of the fluoride (F⁻) must be 0.800 ppm, which is 0.800 parts per million, so the water must have 0.800 g of F⁻/ 1000000 g of the solution. The density of the water at room temperature is 997 kg/m³ = 997x10³ g/m³. So, the concentration of the fluoride will be:

0.800 g of F⁻/ 1000000 g of the solution * 997x10³ g/m³

0.7976 g/m³

The volume of the reservoir is the volume of the cylinder: area of the base * depth. The base is a circumference, which has an area:

A = πR², where R is the radius = 1.01x10² m (half of the diameter)

A = π*(1.01x10²)²

A = 32047 m²

The volume is then:

V = 32047 * 87.32

V = 2.7983x10⁶ m³

The mass of the F⁻ is the concentration multiplied by the volume:

m = 0.7976 * 2.7983x10⁶

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<u>Answer:</u> The final volume of the gas comes out to be 4 L.

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The equation given by this law is:

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where,

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We are given:

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2atm\times 3L=1.5atm\times V_2\\\\V_2=4L

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