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melamori03 [73]
3 years ago
15

Compare and contrast lava and magma

Physics
1 answer:
earnstyle [38]3 years ago
4 0
Magma<span> is made up of molten rock, and it is stored in Earth's crust. </span><span> When the volcano erupts, magma flows out of the volcano, it is usually mixed with steam and gas, which is called lava.</span>
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What is the direction of the current flowing through the wire—left or right? The current flows to the .
muminat

Answer:

right

Explanation:

Current flows from the positive (+ve) terminal of the battery to the negative (-ve). This is called conventional current flow.

Therefore, the electrons are negatively charged and want to get away from the Negative Terminal and go to the Positive Terminal, Hence the electrons move from left to right and current flows from right to left.

5 0
3 years ago
Read 2 more answers
Un niño amarra una soga a una piedra, y la hace girar como en la gráfica. la piedra realiza un M.C.U, girando con una rapidez de
inessss [21]

Answer:

\Delta \theta = 56\,rad

\Delta \theta \approx 3208.564^{\circ}

Explanation:

El ángulo barrido en el intervalo de tiempo dado es (The covered angle in the given time interval is):

\Delta \theta = \omega \cdot \Delta t

\Delta \theta = \left(14\,\frac{rad}{s} \rjght)\cdot (4\,s)

\Delta \theta = 56\,rad

\Delta \theta \approx 3208.564^{\circ}

4 0
3 years ago
How do I calculate the tension in the horizontal string?
matrenka [14]

ANSWER

T₂ = 10.19N

EXPLANATION

Given:

• The mass of the ball, m = 1.8kg

First, we draw the forces acting on the ball, adding the vertical and horizontal components of each one,

In this position, the ball is at rest, so, by Newton's second law of motion, for each direction we have,

\begin{gathered} T_{1y}-F_g=0_{}_{}_{} \\ T_2-T_{1x}=0 \end{gathered}

The components of the tension of the first string can be found considering that they form a right triangle, where the vector of the tension is the hypotenuse,

\begin{gathered} T_{1y}=T_1\cdot\cos 30\degree \\ T_{1x}=T_1\cdot\sin 30\degree \end{gathered}

We have to find the tension in the horizontal string, T₂, but first, we have to find the tension 1 using the first equation,

T_1\cos 30\degree-m\cdot g=0

Solve for T₁,

T_1=\frac{m\cdot g}{\cos30\degree}=\frac{1.8kg\cdot9.8m/s^2}{\cos 30\degree}\approx20.37N

Now, we use the second equation to find the tension in the horizontal string,

T_2-T_1\sin 30\degree=0

Solve for T₂,

T_2=T_1\sin 30\degree=20.37N\cdot\sin 30\degree\approx10.19N

Hence, the tension in the horizontal string is 10.19N, rounded to the nearest hundredth.

8 0
1 year ago
What is loudness of sound?
dedylja [7]
The loudness of sound refer to how loud or soft a sound seems to a listener
6 0
3 years ago
Read 2 more answers
A tray of electronic components contains 15 components, 4 of which are defective. If 4 components are selected, what is the poss
dlinn [17]

Answer:

a) 0.0007326

b) 0.03223

c) 0.2418

d) 0.2418

Explanation:

To find different probabilities for the selection of components among eleven good and four defective components, we will use the Combination.

a) C(4,4) = 1; C(15,4) = 1365

P = \frac{C(4,4)}{C(15,4)} = \frac{1}{1365} = 0.0007326

b) C(4,3) = 4; C(11,1) = 11

P = \frac{C(4,3)*C(11,1)}{C(15,4)} = \frac{4*11}{1365} = 0.03223

c) C(4,2) = 6; C(11,2) = 55

P = \frac{C(4,2)*C(11,2)}{C(15,4)} = \frac{6*55}{1365} = 0.2418

d) C(11,4) = 330

P = \frac{C(11,4)}{C(15,4)} = \frac{330}{1365} = 0.2418

8 0
3 years ago
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