Assume that charge −q is placed on the top plate, and +q is placed on the bottom plate of a parallel plate capacitor. What is th
1 answer:
Answer:
E =
Explanation:
electric field magnitude, E is the intensity of electric force, F per charge, q applied.
thus, E = force per charge = F/q
there are two charges mention in the question. the charge -q placed on top of the plate is the source charge, while the charge, +q place at the bottom plate is the test charge. two charges is needed for an electric force to occur but for electric field calculation, the test charge, +q is used.
the application of coulomb law is used to determined electric force,
F=[ A *(+q)*(-q)]/d²
where,
A is the coulomb law constant = 9.0 x 10⁹ Nm²/C²
+q = test charge on bottom plate
-q = source charge
d = distance of separation between the top and bottom charge
applying the above equation in E
E = [ A *(+q)*(-q)]/d² DIVIDE q
E = [A(-q)]/d²
E =
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To find the answer, we need to know about the thermodynamic processes.
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- The membrane is raptured without applying any external force, thus, dW=0.
- We have the first law of thermodynamic expression as,
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<h3>What is a reversible process?</h3>- Any process which can be made to proceed in the reverse direction is called reversible process.
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Thus, we can conclude that, the final temperature of the system will be equal to the initial temperature, and which is 373K. The work done by the system is 409.8R Joules.
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