Answer:
C. 199.9 s
Explanation:
3 minutes = 3×60 = 180 seconds.
the turtle moves in that time 180×10 = 1800 cm.
in other words the rabbit gave it that much head-start (it does not matter if that was at the begin of in the middle of the race).
the rabbit moves with 10×10cm/s = 100cm/s.
the rabbit needs therefore 1800/100 = 18 seconds for the
1800 cm.
at that time the turtle has added another 18×10 = 180 cm.
for which the rabbit needs 180/100 = 1.8 seconds.
during that time the turtle has added 1.8×10 = 18 cm.
and so on.
in formal mathematics this looks like this :
1800 + 10x = 100x
after x seconds of the rabbit running both will have run the same distance, and it is a tie.
1800 = 90x
x = 20 seconds
so, at that point, the rabbit was actively running for 20 seconds and raced 20×100 = 2000 cm
and the turtle was actively running for 180 + 20 = 200 seconds, and also covered 200×10 = 2000 cm.
but our question tells us that the turtle won by 10 cm.
so, the race was over a little bit before these 200 seconds (for a tie).
this means, the rabbit could not run the last 10 cm for the tie (because the race was over and the turtle had won).
the rabbit would have needed 10/100 seconds for these 10 cm.
as speed = distance/time
we need to divide distance by speed
distance/1 / distance/time
to get time.
so,
10cm/1 / 100cm/s = 10s/100 = 1/10 s
so, we need to deduct this 1/10 s from the 200 seconds of the turtle (and also from the 20 seconds for the rabbit).
the race lasted of course the whole time the turtle was running (while the rabbit was resting, officially still participating in the race with speed 0 for 3 minutes).
and so, the race was 199.9 s long.
