The gravitational force exerted on the moon by the planet when the moon is at maximum distance

is

where G is the gravitational constant, M and m are the planet and moon masses, respectively. This is the minimum force, because the planet and the moon are at maximum distance.
Similary, the gravitational force at minimum distance is

And this is the maximum force, since the distance between planet and moon is minimum.
The problem says that

exceeds

by 11%. We can rewrite this as

Substituing the formulas of Fmin and Fmax, this equation translates into

and so, the ratio between the maximum and the minimum distance is
The answer is A because potential energy is stored up energy which means that it’s not moving
Answer:
<em>the minimum speed that the ball must have so that the cord does not become slack is</em> <em>2.02 m/s.</em>
<em></em>
Explanation:
In order to avoid slack, the centripetal force of the ball must equal its weight at the top of the circle. Therefore,
F_c = F_g
m v² / r = m g
v² = g r
v = √[g r]
v = √[(9.8 m/s²)(0.417 m)]
<em>v = 2.02 m/s </em>
Therefore,<em> the minimum speed that the ball must have so that the cord does not become slack is</em> <em>2.02 m/s.</em>
<span>assuming the pitch is 100yards long, the player runs 100yards to the other goal then a further 50 yards back to the 50-yard line. So he/she runs 150yards in 18s
150/18 = 8.33yards per second average speed.
Initial velocity = 0, average velocity =8.33
Vav = (Vinitial+Vfinal)/2
Vav = 4.16m/s</span>