The total moment of inertia about an axis is : for a ring of mass m and radius straight r attached to a thin rod.
<h3>
Determine the Total moment of Inertia about an axis </h3>
<u>Given data:</u>
mass of ring --> m
radius of ring --> r
mass of rod --> M
Length of rod ---> L ( 2 * radius )
Total Moment of Inertia about an axis = Irod + Iring
where : Irod = moment of inertia of rod, Iring = moment of inertia of ring
Irod = ML² / 3
Iring = 2mr² / 5
moment of inertia around an axis by Iring = I
where ; I = 2mr² / 5 + ML² according to parallel axis theorem
Hence the Total moment of Inertia about an axis is :
Itotal = 2mr²/5 + ML² + ML² / 3
=
Learn more about Moment of inertia : brainly.com/question/6956628
Answer:negative charge, small relative mass, and found outside the nucleus
Explanation:
The electron is one of the subatomic particles. It is negatively charged and has a relatively small or somewhat negligible mass. It is found outside the nucleus on the orbits. The electron is bound to the nucleus by electrostatic forces of attraction in the Bohr's model of the atom.
Answer:
ezrfdjhsetnhtjhsksdjghbksfneunaifghejbcifkikjayhr
Explanation:
mass = 30kg
frictional force = coefficient of friction * (mass * g)
g = 9.8 m/s^2
So:
60N = x * 294 N
x = 60 N / 294 N = 0,2
You can't see beyond a blind turn, so a mirror would allow you to see around the corner.