A helium balloon has an internal pressure of 2.5 atm when it occupies 4.5 L. If it was compressed until it had a pressure of 3.3

Question

3 years ago

9

atm, what would be the final volume? Report your answer with the correct number of significant figures.

2 answers:

steposvetlana [31] · Answer 1 · 2022-01-03T19:45:26+03:00

4 0

Answer: V = 3.4 L

Explanation: Use Boyle's Law to find the new volume. P1V1 = P2V2, derive for V2, then the formula will be V2= P1V1 / P2

V2 = 2.5 atm ( 4.5 L ) / 3.3 atm

= 3.4 L

kakasveta [241] · Answer 2 · 2022-01-03T21:30:08+03:00

4 0

Answer:3.40L

Explanation:

p1v1=p2v2

P1=2.5atm

V1= 4.5L

P2=3.3atm

V2=?

P1V1/P2=V2

V2=2.5*4.5/3.3

V2= 11.25/3.3

V2=3.40L