Puck A, of inertia mm, is attached to one end of a string of length ℓℓ , and the other end of the string is attached to a pivot
so that the puck is free to revolve on a smooth horizontal surface. Puck B, of inertia 20m, is attached to one end of a string of length ℓ/4, and the other end of the string is attached to a second pivot so that BB is also free to revolve. In each case, the puck is held as far as possible from the pivot so that the string is taut and then given an initial velocity v perpendicular to the string.
How does the magnitude of the angular momentum of puck A about its pivot compare with that of puck B about its pivot?
How does the magnitude of the angular momentum of puck A about its pivot compare with that of puck B about its pivot?
1 answer:
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Answer: 1960 N
Explanation:
The bear is sliding down at constant velocity: this means that its acceleration is zero, so the net force is also zero, according to Newton's second law:
There are two forces acting on the bear: its weight W, pulling downward, and the frictional force Ff, pulling upward. Therefore, the net force is given by the difference between the two forces:
From the previous equation, we find that the frictional force is equal to the weight of the bear: