Answer:
a) 51.8 cm³
b) kg/m³ is a dimension of density (mass/volume). The regular unitys for volume are m³, cm³, L, gallons.
Explanation:
a) The density of pure gold is 19.3 g/cm³. When put in water, the piece of gold will occupy a volume, so that the volume of water will be displaced. To know the volume, we must divide the mass for the density (mass must be in grams because of the units of the density)
V = 1000/19.3
V = 51.8 cm³
For a white dwarf star<span> to become explosively active, </span>the gap<span> between the dwarf </span>and therefore the<span> companion </span>should<span> be </span>sufficiently little<span> that the white dwarf's </span>force field will<span> pull matter </span>aloof from<span> the surface of the companion. </span>because of<span> the rotation of the </span>positional representation system<span>, the matter flowing through the mass-transfer stream from the companion star forms a </span>flat <span>disk, </span>known as associate degree<span> accretion disk, </span>that<span> orbits </span>round the white dwarf star<span>.</span>
