I believe a. is the answer.
Answer:
Explanation:
The stoichiometry for this reaction is
The rate for this reaction can be written as
![-r_{NO_2}=-\frac{d\left[NO_2\right]}{dt}=\frac{(0.01-0.008)M}{100s}=2\times{10}^{-5}\frac{M}{s}](https://tex.z-dn.net/?f=-r_%7BNO_2%7D%3D-%5Cfrac%7Bd%5Cleft%5BNO_2%5Cright%5D%7D%7Bdt%7D%3D%5Cfrac%7B%280.01-0.008%29M%7D%7B100s%7D%3D2%5Ctimes%7B10%7D%5E%7B-5%7D%5Cfrac%7BM%7D%7Bs%7D)
This rate of disappearence of 
can be realated to the rate of appearence of 
as follows (the coefficients of each compound are defined by the stoichiometry of the reaction)
Answer:
0.038 g of reactant
Explanation:
Data given:
Heat release for each gram of reactant consumption = 36.2 kJ/g
mass of reactant that release 1360 J of heat = ?
Solution:
As 36.2 kJ of heat release per gram of reactant consumption so first we will convert KJ to J
As we know
1 KJ = 1000 J
So
36.2 kJ = 36.2 x 1000 = 36200 J
So it means that in chemical reaction 36200 J of heat release for each gram of reactant consumed so how much mass of reactant will be consumed if 1360 J heat will release
Apply unity formula
36200 J of heat release ≅ 1 gram of reactant
1360 J of heat release ≅ X gram of reactant
Do cross multiplication
X gram of reactant = 1 g x 1360 J / 36200 J
X gram of reactant = 0.038 g
So 0.038 g of reactant will produce 1360 J of heat.
Answer:
A planet's orbital speed changes, depending on how far it is from the Sun. The closer a planet is to the Sun, the stronger the Sun's gravitational pull on it, and the faster the planet moves. The farther it is from the Sun, the weaker the Sun's gravitational pull, and the slower it moves in its orbit.
Answer:
I think first one..........
