What might cause your stomach pH to become more acidic than normal

An unknown quantity of sugar was completely dissolved in water at 75 degrees Celsius to form a clear and colorless solution. The

Nataly_w [17]

Answer:

67

Explanation:

5 0

3 years ago

The flask contains 10.0 mL of HCl and a few drops of phenolphthalein indicator. The buret contains 0.160 M NaOH. It requires 18.

olchik [2.2K]

Answer:

Approximately $0.291\; \rm M$ (rounded to two significant figures.)

Explanation:

The unit of concentration $\rm M$ is the same as $\rm mol \cdot L^{-1}$ (moles per liter.) On the other hand, the volume of both the $\rm NaOH$ solution and the original $\rm HCl$ solution here are in milliliters. Convert these two volumes to liters:

$V(\mathrm{NaOH}) = 18.2\; \rm mL = 18.2 \times 10^{-3}\; \rm L = 0.0182\; \rm L$ .
$V(\text{$\mathrm{HCl}$, original}) = 10.0\; \rm mL = 10.0\times 10^{-3}\; \rm L = 0.0100\; \rm L$ .

Calculate the number of moles of $\rm NaOH$ in that $0.0182\; \rm L$ of $0.160\; \rm M$ solution:

$\begin{aligned} n(\mathrm{NaOH}) &= c(\mathrm{NaOH})\cdot V(\mathrm{NaOH})\\ &= 0.160\; \rm mol \cdot L^{-1} \times 0.0182\; \rm L \approx 0.00291\; \rm mol\end{aligned}$ .

$\rm HCl$ reacts with $\rm NaOH$ at a one-to-one ratio:

$\rm HCl\; (aq) + NaOH\; (aq) \to NaCl\; (aq) + H_2O\; (l)$ .

Coefficient ratio:

$\displaystyle \frac{n(\mathrm{HCl})}{n(\mathrm{NaOH})} = 1$ .

In other words, one mole of $\rm NaOH$ would neutralize exactly one mole of $\rm HCl$ . In this titration, $0.291\; \rm mol$ of $\rm NaOH\!$ was required. Therefore, the same amount of $\rm HC$ should be present in the original solution:

$\begin{aligned}&n(\text{$\mathrm{HCl}$, original})\\ &= n(\mathrm{NaOH})\cdot \frac{n(\mathrm{HCl})}{n(\mathrm{NaOH})} \\ &\approx 0.00291\; \rm mol \times 1 = 0.00291\; \rm mol\end{aligned}$ .

Calculate the concentration of the original $\rm HCl$ solution:

$\displaystyle c(\text{$\mathrm{HCl}$, original}) = \frac{n(\text{$\mathrm{HCl}$, original})}{V(\text{$\mathrm{HCl}$, original})} \approx \frac{0.00291\; \rm mol}{0.0100\; \rm L} \approx 0.291\; \rm M$ .

5 0

3 years ago

Which set of data would be best illustrated with a graph bar?

polet [3.4K]

Answer:

Graphs should be titled.

Although the bunnies feed foxes, if there are TOO many foxes, they don’t go well; so that looked cyclic to me. It is a good argument.

STUDY VS GRADES is INCREASINGLY

OBVIOUS! I already know what hummingbirds like. Rain can help wash the smoke from forest fires from the air; do you pick one, OK?

Don’t be nervous - study more. I’ve had a great many students, and they not only survived my classes - most THRIVED!

Explanation:

5 0

3 years ago

How are rechargeable batteries recharged? a. Adding new reactants c. Passing electric charge through the reactants b. Changing t

olchik [2.2K]

<span>c. Passing electric charge through the reactants Is the answer to you're question.

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4 0

3 years ago

Each incomplete reaction is a neutralization reaction. Match each equation with the salt formed. 1. H2SO4 + 2NH4OH → ? 2. 2NaOH

sergey [27]

1. H₂SO₄ + 2NH₄OH ⟶ (NH₄)₂SO₄ + 2H₂O

2. 2NaOH + H₂CO₃ ⟶ Na₂CO₃ + 2H₂O

3. HNO₃ + KOH ⟶ KNO₃ + H₂O

<em>Explanation</em>:

Acid + base ⟶ salt + water

Take the H from the acid and the OH from the base to get water.

Then, join what’s left to get the salt. Write the symbol for the metal first.

For example, in equation 3, take the H from HNO₃ and the OH from KOH.

Combining the remaining parts (NO₃ and K) to get the salt, KNO₃.

7 0

3 years ago

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