Help yall 13 points!!
1 answer:
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Answer:
a
b
Explanation:
From the question we are told that
The wavelength is
The number of antinodal planes of the electric field considered is n = 5
The width is mathematically represented as
Generally the frequency the errors was made is mathematically represented as
Here c is the speed of light with value
is the wavelength of the microwave has to be in order for there still to be five antinodal planes of the electric field along the width of the oven, which is mathematically represented as
So
Answer:
Proton’s speed, a short time later when it reaches a point of lower potential is 1.4 x 10⁵ m/s
Explanation:
Given;
initial speed of proton, u = 2.5 x 10⁵ m/s
initial potential, V = 1500 V
mass of proton = 1.67 x 10⁻²⁷ kg
Work done, W = eV= ΔK.E = ¹/₂mu²
eV = ¹/₂mu² (J)
where;
e is the charge of the proton in coulombs
V is the electric potential in volts
m is the mass of the proton in kg
u is the speed of the proton in m/s
Therefore, proton’s speed a short time later when it reaches a point of lower potential is 1.4 x 10⁵ m/s