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3 years ago

How does the planet Venus look to a person standing on the Earth?

Physics

1 answer:

Tema [17]3 years ago

4 0

Answer:

A person would look like an ant if a human was standing next to Venus

Explanation:

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Suppose that at room temperature, a certain aluminum bar is 1.0000 m long. The bar gets longer when its temperature is raised. T

raketka [301]

Answer:

ΔL =0. 000312 m

Explanation:

Given that

At room temperature ( T = 25 ∘C) ,L= 1 m

$L=1+2.4\times 10^{-5}T$

So the length at 13.0 ∘C above room temperature

$L=1+2.4\times 10^{-5}T$

$L=1+2.4\times 10^{-5}\times 13$

L=1.000312 m

So the change in length

ΔL = 1.000312 - 1.0000 m

ΔL =0. 000312 m

4 0

3 years ago

The radius of the aorta is «10 mm and the blood flowing through it has a speed of about 300 mm/s. A capillary has a radius of ab

stealth61 [152]

Answer:

(I). The effective cross sectional area of the capillaries is 0.188 m².

(II). The approximate number of capillaries is $3.74\times10^{9}$

Explanation:

Given that,

Radius of aorta = 10 mm

Speed = 300 mm/s

Radius of capillary $r=4\times10^{-3}\ mm$

Speed of blood $v=5\times10^{-4}\ m/s$

(I). We need to calculate the effective cross sectional area of the capillaries

Using continuity equation

$A_{1}v_{1}=A_{2}v_{2}$

Where. v₁ = speed of blood in capillarity

A₂ = area of cross section of aorta

v₂ =speed of blood in aorta

Put the value into the formula

$A_{1}=A_{2}\times\dfrac{v_{2}}{v_{1}}$

$A_{1}=\pi\times(10\times10^{-3})^2\times\dfrac{300\times10^{-3}}{5\times10^{-4}}$

$A_{1}=0.188\ m^2$

(II). We need to calculate the approximate number of capillaries

Using formula of area of cross section

$A_{1}=N\pi r_{c}^2$

$N=\dfrac{A_{1}}{\pi\times r_{c}^2}$

Put the value into the formula

$N=\dfrac{0.188}{\pi\times(4\times10^{-6})^2}$

$N=3.74\times10^{9}$

Hence, (I). The effective cross sectional area of the capillaries is 0.188 m².

(II). The approximate number of capillaries is $3.74\times10^{9}$

3 0

3 years ago

A circus performer on a pair of stilts exerts a pressure of 32 kPa on the ground. If the performer stands on one stilt, what pre

Agata [3.3K]

Answer:

64 kPa

Explanation:

The pressure exerted by a force on a surface is given by

$p=\frac{F}{A}$

where

p is the pressure

F is the force

A is the area on which the force is exerted

In this problem, let's call:

F = the weight of the performer, which is the force

A = the area of 1 stilt

At the beginning, the performer is standing on both stilts, so the area on which he exerts pressure is 2A. So the pressure is

$p=\frac{F}{2A}=32 kPa$ (1)

Later, he stands on one stilt only. The force exerted is still the same (his weight), however, the area is now reduced to A; therefore, the new pressure is

$p'=\frac{F}{A} = 2(\frac{F}{2A})=2p$

which is twice the value calculated in (1); so, the new pressure is

$p'=2(32)=64 kPa$

3 0

4 years ago

HELP I DON'T PAY ATTENTION ENOUGH

Setler [38]

Answer:

I think 1 is d and 2 is A

Explanation:

but I may be wrong and I am so sorry if I am

8 0

3 years ago

Read 2 more answers

How will the behavior of the gases in the piston chamber change if more pressure is applied to the piston?

allsm [11]

Here molecules of gas remains constant. If more pressure is applied to the piston, gaseous molecules will come closer to each other. Hence their volume decreases and density increases. Hope this helps you.

6 0

3 years ago

Read 2 more answers