<span>When t=0, v=0, d=0
When t=tf, v=41m/s, d=3.5m
We have 2 formulas – the ones corresponding to uniformly accelerated linear movement:
vf=a*t+vo
d=(1/2)*a*t^2+vo*t
Let’s put the data in the formulas:
41m/s=a*t+0=a*t
3.5m=(1/2)*a*t^2+0*t=1/2*a*t^2
You can use a variety of methods to find t and a. I will choose substitution.
t=(41m/s)/a
3.5m=(1/2)*a*((41m/s)/a)^2=(1/2)*a*(41m/s)^2/a^2=(1/2)*(41m/s)^2/a
a=(1/2)*(41m/s)^2/(3.5m)=(1/2)*41^2(m^2/s^2)/(3.5m) a=41^2(m/s^2)/( 2*3.5)=240m/s^2</span>
Answer:
When the volume increases or when the temperature decreases
Explanation:
The ideal gas equation states that:

where
p is the gas pressure
V is the volume
n is the number of moles of gas
R is the gas constant
T is the gas temperature
Assuming that we have a fixed amount of gas, so n is constant, we can rewrite the equation as

which means the following:
- Pressure is inversely proportional to the volume: this means that the pressure decreases when the volume increases
- Pressure is directly proportional to the temperature: this means that the pressure decreases when the temperature decreases
Explanation:
angular velocity is given by


w = 0.626
now tangential velocity is
V = rw
= 25 x 0.626
= 15.65 m/s
Apple on tree branch has potential energy
Answer: F = 776.18N θ = 29.41°
Question:
The magnitude of the resultant force is to be 200 N, directed along the positive y-axis. Determine the magnitude of the force F Find the angle θ.
Attached is the image.
Explanation:
To solve this question we need to resolve the forces to the x and y axis.
For the x axis;
Fcosθ = 700cos15....1
For the y axis;
200 = Fsinθ - 700sin15
Fsinθ = 200 + 700sin15 ...2
Dividing equation 2 by 1
Fsinθ/Fcosθ = (200 + 700sin15)/700cos15
Tanθ = (200 + 700sin15)/700cos15
θ = Taninverse(200 + 700sin15)/700cos15)
θ = 29.41°
From equation 1;
F = 700cos15/cosθ
F = 700cos15/cos29.41
F = 776.18N