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3 years ago

What are advantages of using uranium as an energy source

2 answers:

7 0

-Small amounts of Uranium generate large amounts of energy
-Uranium occurs in huge reserves
-It has a longer lifetime than other non-renewable sources of energy

MariettaO [177]3 years ago

4 0

Question:
What are advantages of using Uranium as an energy source?

Answer(s):
-Small amounts of Uranium generate large amounts of energy
-Uranium occurs in huge reserves
-It has a longer lifetime than other non-renewable sources of energy

-Brainly Answerer

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Based on the sign of E cell, classify these reactions as spontaneous or non spontaneous as written.? assume standard conditions.

sammy [17]

A electrochemical reaction is said to be spontaneous, if $E^{0} cell is positive.$

Answer 1:
Consider reaction: Ni^2+ (aq) + S^2- (aq) ----> + Ni (s) + S (s)

The cell representation of above reaction is given by;
 $S^{2-}/S // Ni^{2+}/Ni$

Hence, $E^{0}cell = E^{0} Ni^{2+/Ni} - E^{0} S/S^{2-}$
we know that, ${E^{0} Ni^{2+}/Ni = -0.25 v$
and ${E^{0} S/ S^{2-} = -0.47 v$

Therefore, $E^{0} cell$ = - 0.25 - (-0.47) = 0.22 v

Since, $E^{0} cell$ is positive, hence cell reaction is spontaneous
.....................................................................................................................

Answer 2:
Consider reaction: Pb^2+ (aq) +H2 (g) ----> Pb (s) +2H^+ (aq)

The cell representation of above reaction is given by;
 $H_{2} / H^{+} // Pb^{2+} /Pb$

Hence, $E^{0}cell = E^{0} Pb/Pb^{2+} - E^{0} H_{2}/H^{+}$
we know that, ${E^{0} Pb^{2+}/Pb = -0.126 v$
and ${E^{0} H_{2}/ H^{+} = -0 v$

Therefore, $E^{0} cell$ = - 0.126 - 0 = -0.126 v

Since, $E^{0} cell$ is negative, hence cell reaction is non-spontaneous.

....................................................................................................................

Answer 3:
Consider reaction: 2Ag^+ (aq) + Cr(s) ---> 2 Ag (s) +Cr^2+ (aq)

The cell representation of above reaction is given by;
 $Cr/Cr^{2+} // Ag^{+}/Ag$

Hence, $E^{0}cell = E^{0} Ag^{+}/Ag - E^{0} Cr/Cr^{2+}$
we know that, ${E^{0} Ag^{+}/Ag = -0.22 v$
and ${E^{0} Cr/ Cr^{2+} = -0.913 v$

Therefore, $E^{0} cell$ = - 0.22 - (-0.913) = 0.693 v

Since, $E^{0} cell$ is positive, hence cell reaction is spontaneous

8 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP! very much appreciated

soldier1979 [14.2K]

Answer:

-Unknown

Explanation:

Questions is not seen properly bro

3 0

2 years ago

What is 0.00000005 in scientific notation, rounded to two significant figures?

KIM [24]

Answer:

5×-10^8

That is the the scintific notation for 0.00000005

Answer=5×-10^8

7 0

3 years ago

What is the difference between the mass number for carbon- 14 and carbon's atomic number of 12.011 amu

Dennis_Churaev [7]

Great question, but I believe you are mixing up atomic number with mass number. Assuming you are, 12.011 amu is the average mass of a carbon atom. For carbon, it can come in three forms: carbon-12, carbon-13, carbon-14. The number following carbon is the mass number of that particular carbon "isotope". The reason the average is so close to 12 is because carbon-12 is by far the most common, so the average should be (and is) very close to 12. Therefore, 12.011 is a weighted average of all carbon molecules, and carbon-14 is a particular carbon molecule that weighs 14 amu.

7 0

3 years ago

Another simple question and I need it bad

podryga [215]

Oh this is extremely hard...i might just die lol jk its the last one measuring cylinder :)

3 0

2 years ago

Read 2 more answers