1.205 × 10²³ atoms of oxygen will be present in 7.51 grams of glycine with formula C₂H5O2N. Details about number of atoms can be found below.
How to calculate number of atoms?
The number of atoms of a substance can be calculated by multiplying the number of moles of the substance by Avogadro's number.
However, the number of moles of oxygen in glycine can be calculated using the following expression:
Molar mass of C₂H5O2N = 75.07g/mol
Mass of oxygen in glycine = 32g/mol
Hence; 32/75.07 × 7.51 = 3.2grams of oxygen in glycine
Moles of oxygen = 3.2g ÷ 16g/mol = 0.2moles
Number of atoms of oxygen = 0.2 × 6.02 × 10²³ = 1.205 × 10²³ atoms
Therefore, 1.205 × 10²³ atoms of oxygen will be present in 7.51 grams of glycine with formula C₂H5O2N.
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The likely thing which happens when two atoms of this element move toward each other is covalent bonding.
<h3>What is Covalent bonding?</h3>
This involves the atoms of element sharing electrons in order to achieve a stable octet configuration.
The element is oxygen which has an atomic number of 8 and needs two electrons to complete its outermost shell which results in the formation of two covalent bonds.
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Accuracy is more of a range
A spontaneous reaction favours the product formation and increases the entropy of the isolated system. The sign of the entropy change will be negative as the product formation is less random.
<h3>What is entropy?</h3>
Entropy is the degree of the disorder or randomness that occurs in the system that lacks available energy and cannot convert the mechanical energy or work.
The entropy of the reaction will be negative as the reactants are present in the gaseous state and the product formed is solid. The product formation was spontaneous and less random.
Therefore, option a. entropy will be negative as product formation is less random.
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