The balanced equation for the neutralisation reaction is as follows
2HNO₃ + Ba(OH)₂ ---> Ba(NO₃)₂ + 2H₂O
stoichiometry of HNO₃ to Ba(OH)₂ is 2:1
number of Ba(OH)₂ mol present - 0.108 mol
1 mol of Ba(OH)₂ neutralises 2 mol of Ba(OH)₂
therefore 0.108 mol of Ba(OH)₂ neutralises - 2 x 0.108 mol = 0.216 mol of HNO₃
Answer:
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Explanation:
This question is describing two chemical equations whereby the concentration of ammonia has to be determined. The first reaction is between 25.00 mL of ammonia and 50.00 mL of 0.100-M HCl whose excess was neutralized with 21.50 mL of 0.050-M Na₂CO₃ and thus, the concentration ammonia in the cloudy solution was determined as 0.114 M.
First of all we need to go over the titration of the excess HCl with Na₂CO₃ by writing the chemical equation it takes place when they react:
Whereas the mole ratio of HCl to Na₂CO₃ is 2:1 and the volume of the HCl leftover is determined as follows:
Next, we infer that the consumed volume of HCl by the ammonia solution was:
Then, we write the chemical equation that takes place between ammonia and HCl:
Whereas the mole ratio is now 1:1, which means that the concentration of ammonia was:
Learn more:
Answer:
677
Explanation:
took the test
it said that it was wrong but then it also said the total bond energy of the reactants is 677 kJ/mol. the correct one was 854, i guess.
Answer:
Explanation:
1.
Given parameters:
Number of moles of CaO = 0.22moles
Unknown:
Mass of CaO = ?
Solution:
Mass, number of moles and molar mass are related using the expression below;
Mass = number of moles x molar mass
Molar mass of CaO = 40 + 16 = 56g/mol
Insert the parameters and solve;
Mass = 0.22 x 56 = 12.32g
2
Given parameters:
Number of moles of NaCl = 0.83moles
Unknown:
mass of NaCl = ?
Solution:
Also,
Mass = number of moles x molar mass
Molar mass of NaCl = 23 + 35.5 = 58.5g/mol
Now insert the parameters and solve;
mass = 0.83 x 58.5
mass = 48.6g
3.
Given parameters:
Number of moles of H₂SO₄ = 0.5moles
Unknown:
mass of H₂SO₄ = ?
Solution:
Mass = number of moles x molar mass
Molar mass of H₂SO₄ = 2(1) + 32 + 4(16) = 98g/mol
Insert the parameters and solve;
Mass = 0.5 x 98 = 49g
