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oksian1 [2.3K]
3 years ago
11

Polygon A is similar to Polygon B. Find the perimeter of Polygon B.

Mathematics
1 answer:
marissa [1.9K]3 years ago
3 0
\bf \textit{ratios relations for similar figures}
\\\\\\
\begin{array}{cccllll}
side&area&volume\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
\frac{s}{s}=\frac{s}{s}&\frac{s^2}{s^2}=\frac{area}{area}&\frac{s^3}{s^3}=\frac{volume}{volume}
\end{array}\\\\
-----------------------------\\\\


\bf thus
\\\\\\
\begin{array}{llll}
\cfrac{\textit{polygon A}}{\textit{polygon B}}\qquad &\cfrac{24^2}{15^2}=\cfrac{128}{x}
\end{array}

solve for "x"
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Answer:

Total distance covered = 436 yards

Step-by-step explanation:

Walking path BE joins the midpoints B and E of the sides AC and AD.

By midsegment theorem,

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m(BE) = \frac{1}{2}[m(CD)]

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From starting point D,

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Total distance covered = 436 yards

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Answer:

c. 10 cm

Step-by-step explanation:

The parallel sides of trapizium are the bases so

base 1(B1) =9cm , base(B2)= 12cm

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the perpendicular distance means the height so lets find the height

area of trapizium= <u>B1 + B2</u> × h

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>2

{105cm}^{2}(the \: given \: area)  =  \frac{9cm(the \: given \: base) + 12cm(the \: given \: base)}{2}  \times h

{105cm}^{2}  =  \frac{21cm}{2}  \times h

now we crisscross

{105cm}^{2} \times 2 = 21cm \times h

{210cm}^{2}  = 21cm \times h

\frac{ {210cm}^{2} }{21cm}  =  \frac{21cm \: }{21cm}  \times h

h = 10 cm

hope u like it ‍❤️‍‍❤️‍‍❤️‍

For any question comment me

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