Heat required to raise the temperature = 159.505 J
<h3>Further explanation</h3>
Given
c = specific heat of Beryllium = 1.825 J/g C
m = mass = 2.3 g
Δt = Temperature difference : 60 - 22 = 38 °C
Required
Heat required
Solution
Heat can be formulated
Q = m.c.Δt
Input the value :
Q = 2.3 x 1.825 x 38
Q = 159.505 J
Answer:
How many grams of potassium chloride, KCl, must be dissolved in 500.0 mL of solution to produce a 1.5 M solution? Answer: g 4. What is the molarity of a solution in which 84.0 grams of sodium chloride, NaCl, is dissolved in 1.25 liters of solution? Answer: M 5.
Explanation:
Answer:
In oxidation reduction reactions, one species gets reduced by taking on electron(s) and another species gets oxidized by losing electrons. They also flow by a wire
Explanation:
The volume in liters of 3245 aluminum cans is 24.8 L.
A recycling center collects 3245 aluminum cans and there are 22 aluminum cans in 1 lb. The mass of 3245 aluminum cans is:

To convert mass to volume, we need the density of aluminum (5.95 lb/L). The volume corresponding to 147.5 lb of aluminum is:

The volume in liters of 3245 aluminum cans is 24.8 L.
You can learn more about density here: brainly.com/question/1841285
Answer:
HCl(aq) + KOH(aq --> KCl(aq) + H₂O(l)
Explanation: