Answer;
= 0.7698 M
Explanation and solution;
AgClO3 ionizes as follows:
AgClO3 ---> Ag^+ + ClO3^-
Moles AgClO3 dissolved ---> (0.393 mol/L) (0.925 L) = 0.424865 mol
From the chemical equation, one mole of AgClO3 dissolving yields one mole of ClO3^- in solution.
Moles ClO3^- = 0.424 865 mol
Similarly;
Mn(ClO3)2 dissolves as follows:
Mn(ClO3)2 ---> Mn^2+ + 2ClO3^-
Moles Mn(ClO3)2 dissolved ---> (0.283 mol/L) (0.685 L) = 0.413139 mol
From the chemical equation, one mole of Mn(ClO3)2 dissolving yields two moles of ClO3^- in solution.
Moles ClO3^- = 0.413139 mol x 2 = 0.826277 mol
Total moles ClO3^- in solution;
0.826277 mol + 0.413139 mol = 1.239416 mol
Total volume of solution ---> 0.925 L + 0.685 L = 1.61 L
Molarity of ClO3^- ---> 1.239416 mol / 1.61 L = 0.7698 M
