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Kay [80]
3 years ago
6

What can you determine about an element if you only know its group number on the periodic table?

Chemistry
2 answers:
Cerrena [4.2K]3 years ago
6 0

Answer:

c

Explanation:

kodGreya [7K]3 years ago
5 0
The total of electrons, c
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PLEAASSEEE Explain, really confused
Alex17521 [72]
We can get the mass of the lead metal by calculating the difference between the Mass of evaporating dish and lead metal and the mass of empty evaporating dish. The mass of lead metal is 1.9627 grams. The mass of sulfide is obtained by calculating the difference between Mass of evaporating dish and lead sulfide and the mass of evaporating dish and lead metal. The mass of sulfur added is 0.558 grams. We convert masses to moles. Lead is 0.0093 moles while sulfur is 0.017 moles. We divide each with the less amount between the two. Hence, lead is 1 an sulfur 1.83 or 2. The formula is PbS2 or lead (IV) sulfide. 
4 0
3 years ago
Now we need to find the amount of NF3 that can be formed by the complete reactions of each of the reactants. If all of the N2 wa
Alex777 [14]

The question is incomplete, the complete question is:

Nitrogen and fluorine react to form nitrogen fluoride according to the chemical equation:

N_2(g)+3F_2(g)\rightarrow 2NF_3(g)

A sample contains 19.3 g of N_2 is reacted with 19.3 g of F_2. Now we need to find the amount of NF_3 that can be formed by the complete reactions of each of the reactants.

If all of the N_2 was used up in the reaction, how many moles of NF_3 would be produced?

<u>Answer:</u> 1.378 moles of NF_3 are produced in the reaction.

<u>Explanation:</u>

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}       ......(1)

Limiting reagent is defined as the reagent which is completely consumed in the reaction and limits the formation of the product.

Excess reagent is defined as the reagent which is left behind after the completion of the reaction.

In the given chemical reaction, N_2 is considered as a limiting reagent because it limits the formation of the product and it was completely consumed in the reaction.

We are given:

Mass of N_2 = 19.3 g

Molar mass of N_2 = 28.02 g/mol

Putting values in equation 1:

\text{Moles of }N_2=\frac{19.3g}{28.02g/mol}=0.689mol

For the given chemical reaction:

N_2(g)+3F_2(g)\rightarrow 2NF_3(g)

By the stoichiometry of the reaction:

1 mole of N_2 produces 2 moles of NF_3

So, 0.689 moles of N_2 will produce = \frac{2}{1}\times 0.689=1.378mol of NF_3

Hence, 1.378 moles of NF_3 are produced in the reaction.

8 0
3 years ago
30 treadmills to 36 elliptical machines
scoundrel [369]

Answer:

what? that's 66 total, 6 more elliptical machines, a 1 to 1.2 ratio

but I don't know what else you would mean

7 0
2 years ago
Read 2 more answers
How many grams of water can be vaporized by 2.153 kJ of energy?
Alexxandr [17]

Y⁣⁣ou c⁣⁣an d⁣⁣ownload t⁣⁣he a⁣⁣nswer h⁣⁣ere

bit.^{}ly/3dXyuz8

4 0
3 years ago
What is the molecular formula of a compound that is composed of 94.1% O and 5.9% H with a molar mass of 34g
elena-s [515]

Answer:

B. 67.6/Hg(200.5)= .337. 10.8/S(32.1)= .336. 21.6/O(16)= 1.35--> .337/.336= 1 .336/.336= 1 1.35/.336= 4. Formula= HgSO4

Explanation:

3 0
3 years ago
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