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zvonat [6]
3 years ago
14

The [H3O+] in a solution is increased to twice the original concentration. Which change could occur in the pH? 2.0 to 4.0 1.7 to

1.4 5.0 to 2.5 8.5 to 6.5 6.8 to 9.8
Chemistry
2 answers:
Natali [406]3 years ago
8 0
Answer: second option: 1.70 to 1.40

Explanation:

1) The definition and formula of pH is - log [H₃O⁺]

2) So, if the original concentration is x and the increased concentration is 2x, you get:

pHi = - logx

pHf = - log 2x = - log 2 - logx

⇒ pHf - pHi = - log2 - logx - (- logx) =  - log2 ≈ - 0.30

⇒ pHi - pHf =  0.30 This is the pH of the final solution (with double concentration of hydronium ions) is 0.30 points lower than the pH of the initial pH.

3) The only choice that shows a decrease of 0.30 in the pH is the second option: 1.70 to 1.40. So that is the answer.


Lady bird [3.3K]3 years ago
3 0
The change that could occur in the pH in the situation, <span>the [H3O+] in a solution is increased to twice the original concentration, is</span> 1.70 to 1.40
 pH formula  is - log [H₃O⁺]



pHi = - logx
pHf = - log 2x = - log 2 - logx
- log2 ≈ - 0.30
pHi - pHf =  0.30 
So there is a decrease of 0.30.
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Explanation:

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4 years ago
How many grams of chlorine gas are present in a 150. liter cylinder of chlorine held at a pressure of 1.00 atm and 0. °C? Group
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Answer:

474 grams of chlorine gas are present in a 150 liter cylinder of chlorine held at a pressure of 1.00 atm and 0 °C

Explanation:

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:  

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where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas.

In this case:

  • P= 1.00 atm
  • V= 150 L
  • n= ?
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Replacing:

1.00 atm* 150 L= n*0.08206 \frac{atm*L}{mol*K} *273 K

Solving:

n=\frac{1.00 atm* 150 L}{0.08206 \frac{atm*L}{mol*K}*273 K}

n= 6.69 moles

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Cl₂=2*35.45 g/mole= 70.9 g/mole

So if 1 mole has 70.9 grams, 6.69 moles of the gas, how much mass does it have?

mass=\frac{6.69 moles*70.9 grams}{1 mole}

mass= 474.321 grams ≅ 474 grams

<u><em>474 grams of chlorine gas are present in a 150 liter cylinder of chlorine held at a pressure of 1.00 atm and 0 °C</em></u>

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