Answer:
While Bohr's atomic model hypothesizes that electrons move in particular energy levels around the nucleus, the electron cloud model suggests that electrons move in an unpredictable pattern but are more likely to be in certain regions than others.
Answer:
Primary active transport
Explanation:
In a cell, the movement of molecules like calcium ions (Ca²⁺), <em>to a region having high solute concentration from a region having low solute concentration, through the cell membrane requires metabolic energy</em> and is known as Primary active transport.
It is given that the concentration of calcium in the cell (0.3%) is greater than the concentration of calcium in the fluid surrounding the cell (0.1%). <em><u>So the calcium ions move into the cell and the cell obtains more calcium. </u></em>
<u>Therefore, the cell obtains more calcium by the process of Primary active transport.</u>
Answer:
first-order reaction is 0.300 s–1 at 400 °C.. ... (in seconds) would it take for the concentration of A to decrease from 0.900 M
Explanation:
yep thats all i know
The percent yield : 79.9%
<h3>Further eplanation
</h3>
Percent yield is the comparison of the amount of product obtained from a reaction with the amount you calculated
General formula:
Percent yield = (Actual yield / theoretical yield )x 100%
An actual yield is the amount of product actually produced by the reaction. A theoretical yield is the amount of product that you calculate from the reaction equation according to the product and reactant coefficients
Reaction
Fe(s)+S(s)⇒FeS(s)
The reaction produces 6.29 g of iron(II) sulfide⇒an actual yield
The maximum amount that can be produced is 7.87 g ⇒ A theoretical yield
Answer:
3) O(g) is an intermediate; 2O3(g)→3O2(g)
Explanation:
The decomposition of ozone to yield oxygen occurs in a sequence of steps. The various non-elementary reactions involved constitute the reaction mechanism. In the sequence of reaction steps O(g) serves as an intermediate.
The overall reaction involves the conversion of two moles of ozone to three moles of oxygen as shown in the answer. Thus the O(g) is merely a reaction intermediate.
