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GenaCL600 [577]
3 years ago
11

How can the shape of a molecule determine its polarity.

Chemistry
2 answers:
Reptile [31]3 years ago
7 0

Answer: D

Explanation:

PilotLPTM [1.2K]3 years ago
4 0

Answer:

The shape of the molecule will determine the direction of each of the individual bond dipoles, and thus, will always play a role in determining the polarity of the molecule as a whole.

Try to see if your answer is correct from that :)

Explanation:

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A car experiences an average acceleration of 5.00 km/hr/s for 3.50 sec. What is the change in velocity of the car?
Mice21 [21]
17.5 km/hr is the answer 
3 0
4 years ago
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a balloon filled with a volume of 1.50 L is compressed to a volume of 0.50 L at a constant rate of temperature. if the initial p
Arisa [49]

Answer:

New pressure P2 = 4.95 atm

Explanation:

Given:

Old volume V1 = 1.50 L

New volume V2 = 0.50 L

Old pressure P1 = 1.65 atm

Find:

New pressure P2

Computation:

P1V1 = P2V2

So,

(1.50)(1.65) = (0.50)(P2)

New pressure P2 = 4.95 atm

5 0
3 years ago
What is the molarity of 50.84 g of Na2CO3 dissolved in 0.400 L solution?
borishaifa [10]

Answer:

1.20 M

Explanation:

Convert grams of Na₂CO₃ to moles.  (50.84 g)/(105.99 g/mol) = 0.4797 mol

Molarity is (moles of solute)/(liters of solvent) = (0.4797 mol)/(0.400 L) = 1.20 M

4 0
3 years ago
What are the empirical and molecular formulas of a hydrocarbon if combustion of 2.10 g of the compound yields 6.59 g co2 and 2.7
mariarad [96]

 The  empirical  formula    of hydrocarbon is  CH2

The  molecular formula  of the  hydrocarbon is  C6H12


    <u><em>Explanation</em></u>

Hydrocarbon  is  made up  of carbon and hydrogen


<h3><u><em> </em></u>Empirical formula  calculation</h3>

 Step 1:  find  the  moles   CO2  and  H2O

moles =mass/molar mass

moles   of CO2 =  6.59 g/ 44 g/mol = 0.15 moles

moles of H2O = 2.70 g / 18 g/mol =  0.15  moles

Step 2: Find the moles  ratio  of Co2:H2O  by diving  each mole by smallest mole(0.15)

that  is  for  CO2 = 0.15/0.15  =1

              For H2O = 0.15/0.15 =1

therefore  the mole ratio  of Co2 : H2O = 1:1  which  implies that 1 mole of Co2  and 1  mole of H2O is  formed  during combustion reaction.


From the  the law of mass conservation the number  of atoms in reactant side  must  be equal to  number of  atoms  in product side

therefore  since  there 1 atom  of C  in product side there  must be 1 atom of C  in reactant  side.

In addition  there is 2 H atom in product  side  which should be the  same  in reactant side.  

From information above the empirical formula is therefore = CH2


Molecular formula  calculation

[CH2}n= 84 g/mol

[12+ (1x2)] n = 84 g/mol

14 n =  84 g/mol

n = 6

multiply the  each subscript  in CH2  by  6

 Therefore the molecular formula = C6H12




5 0
3 years ago
Please help!!! Stoich Question
Greeley [361]

Answer:

4KO₂ + 2CO₂ -> 2K₂CO₃ + 3O₂

<u> Step 1: Find the moles of O₂.</u>

n(O₂) = mass/ Mr.

n(O₂) = 100 / 32 = 3.125 mol

<u>Step 2: Find the ratio between KO₂ and O₂.</u>

        <u>KO₂ </u>    :      <u> O₂</u>

          4        :       3

        4/3       :       1

  (4*3125)/3  :      3.125

=4.167 mol of KO₂

Thus now we know, to produce 100 g of O₂, we need 4.167mol of KO₂

<u>Step 3: Find the mass of KO₂:</u>

<u />

mass = mol * Mr. (KO₂)

Mass = 4.167* 71.1

Mass = 296.25 g

5 0
3 years ago
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