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3 years ago

How can the shape of a molecule determine its polarity.

Chemistry

2 answers:

Reptile [31]3 years ago

7 0

Answer: D

Explanation:

PilotLPTM [1.2K]3 years ago

4 0

Answer:

The shape of the molecule will determine the direction of each of the individual bond dipoles, and thus, will always play a role in determining the polarity of the molecule as a whole.

Try to see if your answer is correct from that :)

Explanation:

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4.82 g of an unknown metal is heated to 115.0∘C and then placed in 35 mL of water at 28.7∘C, which then heats up to 34.5∘C. What

nikitadnepr [17]

<u>Answer:</u> The specific heat of metal is 2.34 J/g°C

<u>Explanation:</u>

To calculate the mass of water, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of water = 1 g/mL

Volume of water = 35 mL

Putting values in above equation, we get:

$1g/mL=\frac{\text{Mass of water}}{35mL}\\\\\text{Mass of water}=(1g/mL\times 35mL)=35g$

When metal is dipped in water, the amount of heat released by metal will be equal to the amount of heat absorbed by water.

$Heat_{\text{absorbed}}=Heat_{\text{released}}$

The equation used to calculate heat released or absorbed follows:

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

$m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]$ ......(1)

where,

q = heat absorbed or released

$m_1$ = mass of metal = 4.82 g

$m_2$ = mass of water = 35 g

$T_{final}$ = final temperature = 34.5°C

$T_1$ = initial temperature of metal = 115°C

$T_2$ = initial temperature of water = 28.7°C

$c_1$ = specific heat of metal = ?

$c_2$ = specific heat of water = 4.186 J/g°C

Putting values in equation 1, we get:

$4.82\times c_1\times (34.5-110)=-[35\times 4.186\times (34.5-28.7)]$

$c_1=2.34J/g^oC$

Hence, the specific heat of metal is 2.34 J/g°C

4 0

3 years ago

Assume that the reaction of aqueous hydrobromic acid solution and potassium hydroxide base undergoes a complete neutralization r

Tamiku [17]

Answer:

$HBr + KOH → KBr + H _{2} O$

$1000 \: ml \: contains \: 0.685 \: moles \\ 55.4 \: ml \: contains \: ( \frac{55.4 \times 0.685}{1000} ) \\ = 0.038 \:moles \\ 1 \: mole \: of \: hydrobromic \: acid \: produces \: 1 \: mole \: of \: water \\ 0.038 \: moles \: produce \: (0.038 \times 1) \\ = 0.038 \: moles \\ 1 \: mole \: of \: water \: weighs \: 18 \: g \\ 0.038 \: moles \: weighs \: (0.038 \times 18) \: g \\ = 0.684 \: g$

0.042 M

1.4

5 0

3 years ago

a glass of water with a mass of 0.35 kg rests on the edge of a desk 0.85 m above the floor given that the acceleration due to gr

bija089 [108]

Answer:

2.92

Explanation:

just took the test

7 0

3 years ago

What is the molarity of 200. mL of solution containing 4.50 moles of ZnCl2?

MariettaO [177]

Answer:

Molarity of solution = 0.9 M

Explanation:

Given data:

Moles of ZnCl₂ = 4.50 mol

Volume of solution = 200 mL

Molarity of solution = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Now we will convert the volume in L.

200 mL×1 L/1000 mL = 0.2L

M = 4.50 mol / 0.2 L

M = 0.9 M

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3 years ago

Please help! This is an exam practice but it’s really hard and I don’t really know it, any help will be appreciated!!

Olin [163]

The question number 1 is cytoplasm
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3 years ago