Phosphorus phosphate and is ionic
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Chemists use reactions to generate a desired product. For the most part, a reaction is only useful if it occurs at a reasonable rate. For example, a reaction that took 8,000 years to complete would not be a desirable way to produce brake fluid. However, a reaction that proceeded so quickly that it caused an explosion would also not be useful (unless the explosion was the desired result). For these reasons, chemists wish to be able to control reaction rates. In order to gain this control, we must first know what factors affect the rate of a reaction. We will discuss some of these factors in this section.
Circular motion. Hope this helps!
Since gas molecules average velocity depends on temperature, oxygen molecules at 25°C are moving faster than oxygen molecules at 0 °C.
According to the kinetic theory of gases, the molecules of a gas are in constant random motion and collide frequently with each other and the walls of the container.
The average speed of gas molecules depends on temperature and molar mass as shown by the relation;
vrms = √3RT/M
The following statement are true among the options provided;
- Oxygen molecules at 25°C are moving faster than oxygen molecules at 0 °C
- Gases exert pressure by colliding with container walls
The following are false among the options provided;
- All hydrogen molecules are moving with the same velocity
- Nitrogen gas exerts more pressure than hydrogen gas because nitrogen molecules are heavier than hydrogen molecules.
- Nitrogen molecules remain suspended in the atmosphere because they are not attracted to Earth by gravitational forces.
Learn more: brainly.com/question/6505878
Answer:
ΔH3 = -110.5 kJ.
Explanation:
Hello!
In this case, by using the Hess Law, we can manipulate the given equation to obtain the combustion of C to CO as shown below:
C(s) + 1/2O2(g) --> CO(g)
Thus, by letting the first reaction to be unchanged:
C(s) + O2(g)--> CO2 (g) ; ΔH1 = -393.5 kJ
And the second one inverted:
CO2(g) --> CO(g) + 1/2O2(g) ; ΔH2= 283.0kJ
If we add them, we obtain:
C(s) + O2(g) + CO2(g) --> CO(g) + CO2 (g) + 1/2O2(g)
Whereas CO2 can be cancelled out and O2 subtracted:
C(s) + 1/2O2(g) --> CO(g)
Therefore, the required enthalpy of reaction is:
ΔH3 = -393.5 kJ + 283.0kJ
ΔH3 = -110.5 kJ
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