. 1s2 2s2 2p6 3s2 3p6 3d10 One point is earned for the correct configuration.
Answer:
is the process by which an atom or a molecule acquires a negative or positive charge by gaining or losing electrons, often in conjunction with other chemical changes.
Answer:
Sodio (Na), elemento químico del grupo de los metales alcalinos (Grupo 1 [Ia]) de la tabla periódica. El sodio es un metal blanco plateado muy suave. El sodio es el metal alcalino más común y el sexto elemento más abundante en la Tierra, y comprende el 2,8 por ciento de la corteza terrestre.
Explanation:
Espero que esto ayude a marcar el MÁS CEREBRAL !!!
Answer:
Hydrosulfuric acid will act as limiting reactant.
Explanation:
Given data:
Mass of iron(III) chloride = 3243.0 g
Mass of hydrosulfuric acid = 511.8 g
Limiting reactant = ?
Solution:
Chemical equation:
2FeCl₃ + 3H₂S → Fe₂S₃ + 6HCl
Number of moles of iron(III) chloride:
Number of moles = mass/molar mass
Number of moles = 3243.0 g/ 162.2 g/mol
Number of moles = 20 mol
Number of moles of hydrosulfuric acid:
Number of moles = mass/molar mass
Number of moles = 511.8 g/ 34.1 g/mol
Number of moles = 15 mol
Now we will compare the moles of both reactant with products
FeCl₃ : Fe₂S₃
2 : 1
20 : 1/2 ×20 = 10
FeCl₃ : HCl
2 : 6
20 : 6/2 ×20 = 60
H₂S : Fe₂S₃
3 : 1
15 : 1/3 ×15 = 5
H₂S : HCl
3 : 6
15 : 6/3 ×15 = 30
Hydrosulfuric acid producing less number of moles of product thus, it will act as limiting reactant.
To obtain the number of moles of electrons, we need to multiply both sides by 1/FE.
<h3>What is electrochemical cell?</h3>
The electrochemical cell is a cell in which energy is produced by chemical reactions which are spontaneous. We can obtain the free energy of an electrochemical cell using the equation; ΔG=-nFE
To make n the subject of the formula, we need to multiply both sides by 1/FE as follows;
.
Learn more about electrochemical cell: brainly.com/question/4592165
