Molar mass NaOH = 39.997 g/mol
number of moles:
n = mass of solute / molar mass
n = 10.0 / 39.997
n = 0.2500 moles
Therefore:
Molarity = moles of solute / volume ( L )
M = 0.2500 / 2.0
M = 0.13 mol/L
Answer B
The answer is the liquid phase
Answer:
1 Mg 1000 kg megagrams to kilograms table
1 dag 10 g dekagrams to grams table
1 kg 100 dag kilograms to dekagrams table
1 g 100 cg grams to centigrams table
1 hg 10000 cg hectograms to centigrams table
1 mg 0.1 cg milligrams to centigrams table
1 hg 100 g hectograms to grams table
1 hg 0.1 kg hectograms to kilograms table
1 ng 1.0E-9 g nanograms to grams table
1 dag 10000 mg
Explanation:
Answer:
C 6 H 12 O 6 + 6O 2 → 6CO 2 + 6H 2 O + 38 ATP
Explanation: