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1 year ago

What happens to temperature of a substance during phase change

Physics

1 answer:

mrs_skeptik [129]1 year ago

5 0

Answer: Nothing

Explanation:

The supplied energy is used for phase transition, not molecule kinetic energy.

Example: ice cannot be heated above 0Cº when it is being melted. Heat is consumed for phase change during its transition from solid to liquid. Only after all ice has melted, the temperature will rise until the next phase transition - vapor.

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The radius of curvature is smaller at the top than on the sides so that the downward centripetal acceleration at the top will be

kap26 [50]

Answer:

$v = 14.86 m/s$

Explanation:

As we know that the force equation at the top is given as

$\frac{mv^2}{R} = ma$

now we know that

$a_c = 1.5 g$

so we have

$\frac{v^2}{R} = 1.5 g$

$v = \sqrt{1.5 Rg}$

so we will have

$v = \sqrt{1.5(15)(9.81)}$

$v = 14.86 m/s$

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2 years ago

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Reil [10]

Electrical energy in the charger and cable

Chemical energy in the battery of the mobile phone

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2 years ago

Which excited electron has the lowest energy?

bearhunter [10]

Answer:

The lowest energy of electron is the ground state.

Explanation:

4 0

2 years ago

Read 2 more answers

What does the term "speed" describe?

Blababa [14]

The cyclist who travels 20 kilometers per hour for 15 kilometers

7 0

2 years ago

A satellite orbits a planet of unknown mass in a circular orbit of radius 2.3 x 104 km. The gravitational force on the satellite

sladkih [1.3K]

Answer:

The kinetic energy is $KE = 7.59 *10^{10} \ J$

Explanation:

From the question we are told that

The radius of the orbit is $r = 2.3 *10^{4} \ km = 2.3 *10^{7} \ m$

The gravitational force is $F_g = 6600 \ N$

The kinetic energy of the satellite is mathematically represented as

$KE = \frac{1}{2} * mv^2$

where v is the speed of the satellite which is mathematically represented as

$v = \sqrt{\frac{G M}{r^2} }$

=> $v^2 = \frac{GM }{r}$

substituting this into the equation

$KE = \frac{ 1}{2} *\frac{GMm}{r}$

Now the gravitational force of the planet is mathematically represented as

$F_g = \frac{GMm}{r^2}$

Where M is the mass of the planet and m is the mass of the satellite

Now looking at the formula for KE we see that we can represent it as

$KE = \frac{ 1}{2} *[\frac{GMm}{r^2}] * r$

=> $KE = \frac{ 1}{2} *F_g * r$

substituting values

$KE = \frac{ 1}{2} *6600 * 2.3*10^{7}$

$KE = 7.59 *10^{10} \ J$

7 0

3 years ago