Answer:
Equation 3
Explanation:
It combines all the gas laws and it is called the ideal gas equation
3.98 x 10⁻¹⁹ Joule
<h3>Further explanation</h3>
<u>Given:</u>
The green light has a frequency of about 6.00 x 10¹⁴ s⁻¹.
<u>Question:</u>
The energy of a photon of green light (in joules).
<u>The Process:</u>
The energy of a photon is given by ![\boxed{\boxed{ \ E = hf \ }}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cboxed%7B%20%5C%20E%20%3D%20hf%20%5C%20%7D%7D)
- E = energy in joules
- h = Planck's constant 6.63 x 10⁻³⁴ Js
- f = frequency of light in Hz (sometimes the symbol f is written as v)
Let us find out the energy of the green light emitted per photon.
![\boxed{ \ E = (6.63 \times 10^{-34})(6.00 \times 10^{14}) \ }](https://tex.z-dn.net/?f=%5Cboxed%7B%20%5C%20E%20%3D%20%286.63%20%5Ctimes%2010%5E%7B-34%7D%29%286.00%20%5Ctimes%2010%5E%7B14%7D%29%20%5C%20%7D)
Thus, we get a result of ![\boxed{\boxed{ \ E = 3.98 \times 10^{-19} \ J \ }}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cboxed%7B%20%5C%20E%20%3D%203.98%20%5Ctimes%2010%5E%7B-19%7D%20%5C%20J%20%5C%20%7D%7D)
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Notes
- When an electron moves between energy levels it must emit or absorb energy.
- The energy emitted or absorbed corresponds to the difference between the two allowed energy states, i.e., as packets of light called photons.
- A higher energy photon corresponds to a higher frequency (shorter wavelength) of light.
<h3>Learn more</h3>
- The energy of the orange light emitted per photon brainly.com/question/2485282#
- Determine the density of our sun at the end of its lifetime brainly.com/question/5189537
- Find out the kinetic energy of the emitted electrons when metal is exposed to UV rays brainly.com/question/5416146
Keywords: green light, frequency, the energy, a photon, Planck's constant, electrons, emitted, wavelength, joules