Answer:
CH3O
Explanation:
We can get the answer through calculations as follows.
From the mass of carbon iv oxide produced, we can get the number of moles of carbon produced. We first divide the mass by the molar mass of carbon iv oxide. The molar mass of carbon iv oxide is 44g/mol
The number of moles of carbon iv oxide is 4.30/44 = 0.0977 mole
Since there is only one carbon atom in CO2, the number of moles of carbon is same as above
The mass of carbon in the compound is simply the number of moles multiplied by the atomic mass unit. The atomic mass unit of carbon is 12. The mass of carbon in the compound is thus 12 * 0.0977= 1.173g
From the number of moles of water, we can get the number of moles of hydrogen. To get the number of moles of water, we need to divide the mass of water by its molar mass. Its molar mass is 18g/mol. The number of moles here is thus 2.35/18 = 0.131 mole
But there are 2 atoms of hydrogen in 1 mole of water and thus, the number of moles of hydrogen is 2 * 0.131 = 0.262 mole
The mass of hydrogen is thus 0.262* 1 = 0.262g
The mass of oxygen equals the mass of the compound minus that of hydrogen and that of carbon.
= 3 - 0.262 - 1.173 = 1.565g
The number of moles of oxygen is the mass of oxygen divided by its atomic mass unit.
That equals 1.565/16 = 0.0978moles
The empirical formula can be obtained by dividing the number of moles of each by the smallest which is that of carbon
H = 0.262/0.0977 = 2.7 = 3
O = 0.0978/0.0977 = 1
C = 0.0978/0.0977= 1
We multiply through by 3 to give CH3O
