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tekilochka [14]
2 years ago
9

A skater is spinning at 15.0 rad/s with a rotational inertia of 8.0 kg m? If she changes her rotational inertia to 5.0 kg mº, wh

at is her new angular velocity (in rad/s)?
Physics
1 answer:
mixas84 [53]2 years ago
3 0

Answer:Idrk man

Explanation:

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Answer:

106.7 N

Explanation:

We can solve the problem by using the impulse theorem, which states that the product between the average force applied and the duration of the collision is equal to the change in momentum of the object:

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where

F is the average force

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In this problem:

m = 0.200 kg

u = 20.0 m/s

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Solving for F,

F=\frac{m(v-u)}{\Delta t}=\frac{(0.200 kg) (-12.0 m/s-20.0 m/s)}{0.06 s}=-106.7 N

And since we are interested in the magnitude only,

F = 106.7 N

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Solve 1 for x if a=-9.8, v=2.7, and t= 35​
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