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mel-nik [20]
2 years ago
7

Explain 3 sources of carbon dioxide production and explain how the production of CO2 can lead to global warming.

Chemistry
1 answer:
prisoha [69]2 years ago
3 0

Answer:

Natural sources include decomposition, ocean release and respiration. Human sources come from activities like cement production, deforestation as well as the burning of fossil fuels like coal, oil and natural gas.

Explanation:

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PLS HELP MEEEE I REALLY NEED HELP
yawa3891 [41]

Answer:

the answeer is c.

Explanation:

3 0
3 years ago
(03.04 MC) What is the correct name for PH3? (3 points) Monophosphorus trihydride Monophosphorus hydroxide Phosphorus hydride Ph
Paul [167]

Answer: phosphorus trihyde

Explanation: just took the quiz and got this answer

4 0
3 years ago
Read 2 more answers
At a certain temperature the rate of this reaction is first order in HI with a rate constant of 0.0632 s
kirza4 [7]

Answer:

28.037\ \text{s}

Explanation:

[A]_0 = Initial concentration = 1.28 M

[A] = Final concentration = 0.17[A]_0

k = Rate constant = 0.0632 s

t = Time taken

For first order reaction we have the relation

kt=\ln\dfrac{[A]_0}{[A]}\\\Rightarrow t=\dfrac{\ln\dfrac{[A]_0}{[A]}}{k}\\\Rightarrow t=\dfrac{\ln\dfrac{[A]_0}{0.17[A]_0}}{0.0632}\\\Rightarrow t=28.037\ \text{s}

Time taken to reach the required concentration would be 28.037\ \text{s}.

8 0
3 years ago
Suppose you have 1.00 l of an aqueous buffer containing 60.0 mmol acetic acid (pka = 4.76) and 40.0 mmol acetate. what volume of
butalik [34]
Required pH = 4.93
- OH⁻ from NaOH reacts with CH₃COOH giving CH₃COO⁻ and H₂O 
- Let the volume of 3.5 M NaOH be x ml
Moles of NaOH = Moles of OH⁻ = Molarity * x ml = 3.5x mmol
- The reaction table for moles is as follows:
                   CH₃COOH + OH⁻ →  CH₃COO⁻ + H₂O
Initial               60             3.5x          40
Change         -3.5x         -3.5x         +3.5x
Final            (60-3.5x)       0           (40+3.5x)
- Substitute in Henderson equation and solve for x:
pH = pKa + log \frac{[CH_{3}COO^-]}{[CH_3COOH]}
4.93 = 4.76 + log \frac{(40+3.5x)}{(60-3.5x)}
0.17 = log \frac{(40+3.5x)}{(60-3.5x)}
\frac{(40+3.5x)}{(60-3.5x)} = 1.479
x = 5.62 ml NaOH required 
4 0
3 years ago
A conjugate base is the species that
malfutka [58]
A conjugate base is the species that D. Remains after an acid has given up a single proton.

It is the deprotonated form of the acid.
8 0
3 years ago
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