The mass of sulfur trioxide (in g) produced when 100 g of each reactant is present is 166.64 grams
calculation
find the moles of each reactant
moles = mass/molar mass
moles of SO2= 100 g/ 64 = 1.5625 moles
moles of O2= 100/32= 3.125 moles
oxygen is the limiting reagent therefore by use of mole ratio of O2:SO3 which is 3:2 the moles of SO3= 3.125 x2/3=2.083 moles
mass of SO3= molar mass x moles
= 2.083 moles x80 g/mol= 166.64 grams
Answer:
eg=linear, mg=linear
Explanation:
First of all, it must be stated that most triatomic molecules are either linear or bent. This depends on the electron geometry of the molecule and the number of bonding groups, multiple bonds and lone pairs present.
CO2 contains four regions of electron density and two bonding groups. For a specie containing two bonding groups, a linear molecular geometry is expected with an angle of 180°.
For a specie having two bonding groups and no lone pairs with multiple bonds, the expected electron geometry is also linear.
Answer:
1.67×10^25 molecules
Explanation:
No of molecules = no of moles × Avogadros number
No of moles= mass in gram / molar mass
No of moles of water in given sample = 500.3/18
= 27.79 moles
No of molecules = 27.79× 6.02×10^ 23
= 167.32×10^23 or 1.67×10^25
Answer:
In general, liquids tend to get “thinner” when their temperature increases. For example, honey and oil tend to flow better at higher temperatures. Therefore, increasing temperature decreases viscosity. In general, the liquids tend to expand when their temperature increases
Explanation:
I think it would be either dead bodies or rocks? i dont really understand too well but sorry if this doesn’t help!! :((