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adoni [48]
3 years ago
5

4. If you put 1 mL of coffee into 9 mL of water, how much was the coffee diluted?

Chemistry
2 answers:
garri49 [273]3 years ago
7 0

1 in 10, or 1/10, or 0.1 dilution factor It may be wrong but this is what I have!

VARVARA [1.3K]3 years ago
7 0

Answer : The coffee diluted was, 1 in 10, or 1/10, or 0.1 dilution factor.

Explanation :

Dilution : It is defined as the solute concentration of a solution decreased by adding the solvent.

The dilution factor for 1 ml of coffee into 9 ml of water is:

\frac{\text{Amount transferred}}{\text{Total amount}}=\frac{\text{Amount transferred}}{\text{(amount transferred}+\text{amount water added)}}

Now put all the given values in this expression, we get the dilution factor for coffee.

\frac{\text{Amount transferred}}{\text{(amount transferred}+\text{amount water added)}}=\frac{1}{(1+9)}=\frac{1}{10}=0.01

Therefore, the coffee diluted was, 1 in 10, or 1/10, or 0.1 dilution factor.

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The sum of (4) + 4×(3) - (2) - 2×(1) - 2×(5) is:

(4) X(s) + O₂(g) ⟶ XO₂(s) ΔH = −639.1 kJ

+4×(3) 2H₂(g) + 2Cl₂(g) ⟶ 4HCl(g) ΔH = −369,2 kJ

-(2) XCl₄(s) ⟶ X(s) + 2Cl₂(g) ΔH = -356,9 kJ

-2×(1) 2H₂O(g) ⟶ 2H₂(g) + O₂(g) ΔH = +483,6 kJ

-2×(5) 2H₂O(l) ⟶ 2H₂O(g) ΔH = +88.0 kJ

= <em>XCl₄(s) + 2H₂O(l) ⟶ XO₂(s) + 4HCl(g)</em>

Where ΔH is:

ΔH = -639,1 kJ -369,2 kJ -356,9 kJ +483,6 kJ +88,0 kJ

<em>ΔH = -793,6 kJ</em>

I hope it helps!

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