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adoni [48]
3 years ago
5

4. If you put 1 mL of coffee into 9 mL of water, how much was the coffee diluted?

Chemistry
2 answers:
garri49 [273]3 years ago
7 0

1 in 10, or 1/10, or 0.1 dilution factor It may be wrong but this is what I have!

VARVARA [1.3K]3 years ago
7 0

Answer : The coffee diluted was, 1 in 10, or 1/10, or 0.1 dilution factor.

Explanation :

Dilution : It is defined as the solute concentration of a solution decreased by adding the solvent.

The dilution factor for 1 ml of coffee into 9 ml of water is:

\frac{\text{Amount transferred}}{\text{Total amount}}=\frac{\text{Amount transferred}}{\text{(amount transferred}+\text{amount water added)}}

Now put all the given values in this expression, we get the dilution factor for coffee.

\frac{\text{Amount transferred}}{\text{(amount transferred}+\text{amount water added)}}=\frac{1}{(1+9)}=\frac{1}{10}=0.01

Therefore, the coffee diluted was, 1 in 10, or 1/10, or 0.1 dilution factor.

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A laboratory analysis of a sample finds it is composed of 38.8% carbon, 16.2% hydrogen, and 45.1% nitrogen. What is its empirica
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Answer: The empirical formula for the given compound is CH_5N

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Percentage of C = 38.8 %

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Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of C = 38.8 g

Mass of H = 16.2 g

Mass of N = 45.4 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{38.8g}{12g/mole}=3.23moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{16.2g}{1g/mole}=16.2moles

Moles of Nitrogen = \frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{45.4g}{14g/mole}=3.24moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 3.23 moles.

For Carbon = \frac{3.23}{3.23}=1

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Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : N = 1 : 5 : 1

Hence, the empirical formula for the given compound is C_1H_5N_1=CH_5N

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