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adoni [48]
3 years ago
5

4. If you put 1 mL of coffee into 9 mL of water, how much was the coffee diluted?

Chemistry
2 answers:
garri49 [273]3 years ago
7 0

1 in 10, or 1/10, or 0.1 dilution factor It may be wrong but this is what I have!

VARVARA [1.3K]3 years ago
7 0

Answer : The coffee diluted was, 1 in 10, or 1/10, or 0.1 dilution factor.

Explanation :

Dilution : It is defined as the solute concentration of a solution decreased by adding the solvent.

The dilution factor for 1 ml of coffee into 9 ml of water is:

\frac{\text{Amount transferred}}{\text{Total amount}}=\frac{\text{Amount transferred}}{\text{(amount transferred}+\text{amount water added)}}

Now put all the given values in this expression, we get the dilution factor for coffee.

\frac{\text{Amount transferred}}{\text{(amount transferred}+\text{amount water added)}}=\frac{1}{(1+9)}=\frac{1}{10}=0.01

Therefore, the coffee diluted was, 1 in 10, or 1/10, or 0.1 dilution factor.

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Explanation:

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Na transfers 1 electron to CL to form Ionic bond.

While

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(a) Given that Ka for acetic acid is 1.8 X 10^-5 and that for hypochlorous acid is 3.0 X 10^-8, which is the stronger acid? (b)
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Answer:

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Kb(OAc⁻) = 5.5 x 10⁻¹⁰

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Explanation:

Assume 0.10M HOAc => H⁺ + OAc⁻  with Ka = 1.8 x 10⁻⁵

=> [H⁺] = √Ka·[Acid] =√(1.8 x 10⁻⁵)(0.10) M = 1.3 x 10⁻³M H⁺

Assume 0.10M HClO => H⁺ + ClO⁻ with Ka = 3 x 10⁻⁸

=> [H⁺] = √(3 x 10⁻⁸)(0.10)M = 5.47 x 10⁻⁵M H⁺

HOAc delivers more H⁺ than HClO and is more acidic.

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4 0
3 years ago
. What is the mass of 23.56 moles of Glucose<br> ples of Glucose - C6H1206?
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Answer:

4244.48 g to the nearest hundredth.

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Answer: The temperature of the gas reduced to 400K.

Explanation:

Stated that ; The pressure remains the same, that is initial and final pressure equals 1atm.

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Therefore, when the volume is halved, the temperature reduced also to half ( 400K)

3 0
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