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adoni [48]
3 years ago
5

4. If you put 1 mL of coffee into 9 mL of water, how much was the coffee diluted?

Chemistry
2 answers:
garri49 [273]3 years ago
7 0

1 in 10, or 1/10, or 0.1 dilution factor It may be wrong but this is what I have!

VARVARA [1.3K]3 years ago
7 0

Answer : The coffee diluted was, 1 in 10, or 1/10, or 0.1 dilution factor.

Explanation :

Dilution : It is defined as the solute concentration of a solution decreased by adding the solvent.

The dilution factor for 1 ml of coffee into 9 ml of water is:

\frac{\text{Amount transferred}}{\text{Total amount}}=\frac{\text{Amount transferred}}{\text{(amount transferred}+\text{amount water added)}}

Now put all the given values in this expression, we get the dilution factor for coffee.

\frac{\text{Amount transferred}}{\text{(amount transferred}+\text{amount water added)}}=\frac{1}{(1+9)}=\frac{1}{10}=0.01

Therefore, the coffee diluted was, 1 in 10, or 1/10, or 0.1 dilution factor.

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3 years ago
III. For the following four sections: If you are given the formula, name the
serious [3.7K]

Answer:

15.Potassium oxide

16.Calcium chloride

17.Aluminium sulphide

18.CaS

Explanation:

15.K is the chemical symbol of Potassium and generally the name of the non-metal at the end of a formula has the suffix '-ide' and since O is oxygen, the name becomes Potassium oxide.

16. The same applies here. Ca is Calcium and Cl is Chlorine but since its the non-metal at the end, it ends in -ide. So Calcium chloride.

17.The same applies here too. Al is Aluminium and S is Sulphur so Aluminium sulphide.

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3 years ago
What can occur in physical change ?
Alexandra [31]

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5 0
3 years ago
An iron(iii) sulfate hydrate is 18.4% water. What is the formula of the hydrate? What is the name of the hydrate?
aleksley [76]

Answer:- Formula of the hydrate is Fe_2(SO_4)_3.5H_2O and it's name is Iron(III)sulfate pentahydrate.

Solution:- As per the given information, there is 18.4% water in the hydrate. If we assume the mass of the hydrate as 100 grams then there would be 18.4 grams of water and 81.6 grams of Iron(III)sulfate present in the hydrate.

Molar mass for Iron(III)sulfate is 399.88 gram per mol and the molar mass for water is 18.02 gram per mol.

We will calculate the moles of Iron(III)sulfate and water present in the compound on dividing their grams by their molar masses as:

81.6gFe_2(SO_4)_3(\frac{1mol}{399.88g})

= 0.204molFe_2(SO_4)_3

18.4gH_2O(\frac{1mol}{18.02g})

= 1.02molH_2O

Now, the next step is to calculate the mol ratio and for this we divide the moles of each by the least one of them means whose moles are less. Here, the moles of Iron(III)sulfate are less than moles of water. So, we divide the moles of each by 0.204.

Fe_2(SO_4)_3=\frac{0.204}{0.204}  = 1

H_2O=\frac{1.02}{0.204} = 5

There is 1:5 mol ratio between Iron(III)sulfate and water. So, the formula of the hydrate is Fe_2(SO_4)_3.5H_2O and the name of the hydrate is Iron(III)sulfate pentahydrate.


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